All categories

2 years ago

What are the elements that make up the compound, and what are some properties of these elements?

Chemistry

1 answer:

nekit [7.7K]2 years ago

7 0

Answer: Below (=

Explanation:

The properties of a compound depend not only on which atoms the compound contains, but also on how the atoms are arranged. Atoms of carbon and hydrogen, for example, can combine to form many thousands of different compounds.

You might be interested in

You wish to prepare an HC2H3O2 buffer with a pH of 4.24. If the pKa of is 4.74, what ratio of C2H3O2 /HC2H3O2 must you use?

LenaWriter [7]

To solve this problem, we can use the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:

pH = pKa + log ([base]/[acid]) ---> 1

Where,

[base] = concentration of C2H3O2 in molarity or moles

[acid] = concentration of HC2H3O2 in molarity or moles

For the sake of easy calculation, let us assume that:

[base] = 1

[acid] = x

Therefore using equation 1,
4.24 = 4.74 + log (1 / x)

log (1 / x) = - 0.5

1 / x = 0.6065

x = 1.65

The required ratio of C2H3O2 /HC2H3O2 is 1:1.65 or 3:5.

3 0

3 years ago

What's ligand and how are they classified

KATRIN_1 [288]

Explanation:

Ligands: In co-ordination chemistry ligands are ion, molecule or any species which donates electron pair to central metal atom.

Depending on the type of interaction Ligands are of three types.

Sigma donor only
sigma as well as pi donor
pi acceptor ligand

let's understand each type of Ligands individually & in more detail.

1 - Sigma donor only: This is a unidirectional interaction, in which filled ligand overlaps (head to head) with central metal atom/ion & donates pair of electron in the LUMO of metal.

generally all the molecules of 2nd period without pi bond comes in this category, below are few example of sigma donor ligands,

$\small \sf NH_3, H_2O, CH_3^-, H^-, R-OH, R-NH_3, etc$

2- Pi donor: This in also a unidirectional interaction between ligand & central metal atom but the along with head to head overlap, side overlapping takes place.

generally protonated neutral molecules who have more than one pair to donate show such interaction, for e.g.

NH3 have two lone pair to donate but the energy level of both the lone pairs are different hence when it is neutral it only donates one pair of electron. but when NH3 is protonated to NH2- it have two electron pairs (negative charge+ lone pair) to donate & both the pairs have same energy level. example of such ligands are below,

$\sf \small NH_2^-, OH^-, R-O^-, R-NH^-, F^-, Cl^-, Br^- SH^- etc$

3- Pi acceptor ligand: This is a bidirectional interaction between ligand & central metal atom/ion, the filled orbital of ligand undergoes head to head to overlap with vacant orbital of central metal atom, & filled D orbital of central metal donates their pair to vacant LUMO of ligand.

depending on the LUMO pi acceptor ligands are further classified into two categories.

$d\pi - \sigma* \small \sf When \: lumo \: is \: \sigma*\\ d\pi - \pi* \small \: \sf When \: lumo \: is \: \pi*$

The dπ-σ* is seen in molecules of 3rd period onwards without pi bond for e.g.

PH3, PR3, AsR3 & SR2 etc

The dπ-π* is seen in molecules of 2nd or3rd period with pi bond for e.g.

CO C N- SC N^- etc

Thanks for joining brainly community!

8 0

2 years ago

Genetic Information DNA is coiled into chromosomes in a cell’s .

puteri [66]

Nucleus is the right answer i guess

7 0

3 years ago

Caclulate the pH of a solution with a hydrogen ion concentration of 1X10-7

LUCKY_DIMON [66]

Answer:

The pH of the solution is 7.00 .

Explanation:

The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:

pH = -log (H30 +)

pH= -log (1x10^-7)

pH= 7.00

7 0

3 years ago

3.0 moles of nitrogen is reacted with 11.0 moles of hydrogen to produce ammonia according to the chemical equation shown below.

Ne4ueva [31]

Answer:

Explanation:

From the equation, we can say that we need thrice the number of hydrogen than that of nitrogen

we are given 3 moles of nitrogen and 11 moles of hydrogen

but thrice the number of moles of nitrogen is 9, hence we have hydrogen in excess or Hydrogen is the excess reagent

Since we had 11 moles of Hydrogen and we only needed 9, 2 moles of hydrogen are left over

From the equation, we can see that the moles of ammonia formed will be twice the moles of nitrogen

Since 3 moles of nitrogen are used, the reaction will give us 6 moles of Ammonia and NOT 12 moles, therefore c is the correct answer

Since we have hydrogen in excess, our reaction is being limited because we have less Nitrogen, Hence Nitrogen is the Limiting Reagent

5 0

3 years ago