Answer:
Moles of gas collected = 0.952 mole
Explanation:
To calculate the number of moles of the gas collected, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 702 mmHg
V = Volume of the gas = 25.0 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of gas = ?
Putting values in above equation, we get:
<u>Moles of gas collected = 0.952 mole</u>
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The percent composition by mass for sodium (Na) in Sodium phosphate (Na₃PO₄) : 42.07%
<h3>Further explanation</h3>
Given
Compound of Sodium phosphate (Na₃PO₄)
Required
The percent composition by mass for sodium (Na)
Solution
<em>The Comparative Law (Proust ) : compounds are formed from elements with the same Mass Comparison</em>
MW Na₃PO₄ = 163,94 g/mol
Ar Na=22,989769g/mol

Answer: 3.94 atm
Explanation:
Given that,
Initial pressure (P1) = 3.80atm
Initial temperature (T1) = 25°C
since the standard unit of temperature is Kelvin, convert 25°C to Kelvin
(25°C + 273= 298K)
Final pressure P2 = ?
Final temperature T2 = 36°C
(36°C + 273= 309K)
Since pressure and temperature are given while volume is held constant, apply the formula for Pressure's law
P1/T1 = P2/T2
3.80 atm / 298K = P2 / 309K
To get the value of P2, cross multiply
3.80 atm x 309K = P2 x 298K
1174.2 atm•K = 298K•P2
Divide both sides by 298K
1174.2 atm•K/298K = 298K•P2/298K
3.94 atm = P2
Thus, the final pressure is 3.94 atm