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3 years ago

Which object forms when a supergiant runs out of fuel? a red giant a black hole a white dwarf a neutron star

2 answers:

6 0

The supergiant stars are considered as the biggest stars in the universe. They can be thousands of times larger than the Sun and can exhibit a mass up to 100 times more. In the case when the supergiants run out of fuel or hydrogen they give rise to a supernova, and then either turn into a black hole or a neutron star.

A neutron star refers to a very dense but little star, comprising neutrons and emerges as the core of the dead supergiant.

A black hole refers to a location in space, more accurately in time-space, which is most generally known for its drastic gravitational influence and for its dark color.

NeTakaya3 years ago

5 0

I believe the correct answer would be "neutron star"

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HgC2H6

Fittoniya [83]

Answer:

The number of molecules= 1.33 × 10∧22 molecules

percentage of mercury = 87%

Explanation:

Given data:

mass of dimethyl mercury = 5.10 g

number molecules of dimethyl mercury in 5.10 g = ?

percentage of mercury = ?

Solution:

First of all we will calculate the molar mass of dimethyl mercury.

molar mass of HgC2H6 = 1×200.6 + 2×12 + 6×1 = 230.6 g/mol

we know that,

230.6 g of HgC2H6 = 1 mol = 6.02 × 10∧23 molecules.

For the 5.10 g of sample:

5.10 g/230 g/mol = 0.022 moles of HgC2H6

now we will multiply these number of moles with Avogadro number to get number of molecules in 5.10 g of sample.

0.022 × 6.02 × 10∧23 molecules = 0.133 × 10∧23 molecules or

1.33 × 10∧22 molecules.

Percentage of mercury:

Formula:

percentage = (atomic number of Hg × total number of atoms of Hg/ molar mass of HgC2H6) × 100

% age of Hg = (200.6 g/mol× 1/ 230.6 g/mol) × 100

%age of Hg = 0.869 × 100

%age of Hg = 86.99 % or 87 %

6 0

2 years ago

What is the correct name for the compound, P2O5?

VikaD [51]

DiPhosphorus pentoxide or pentaoxide

4 0

2 years ago

Read 2 more answers

Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide: C6H12O6

attashe74 [19]

Answer:

Mass of ethanol obtained is 260.682 grams.

Volume of the ethanol obtained is 0.3304 L.

Explanation:

$C_6H_{12}O_6\rightarrow 2C_2H_5OH + 2CO_2$

Moles of glucose = $\frac{510.6 g}{180 g/mol}=2.833 mol$

According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.

Then 2.833 moles of glucose will give :

$\frac{2}{1}\times 2.8333 mol=5.667 mol$

Mass of 5.667 moles of an ethanol :

5.667 mol × 46 g/mol = 260.682 g

Volume of ethanol = V

Density of the ethanol = 0.789 g/mL

$Density=\frac{Mass}{Volume}$

$0.789 g/mL=\frac{260.682 g}{V}$

$V=\frac{260.682 g}{0.789 g/mL}=330.40 mL = 0.3304 L$

Mass of ethanol obtained is 260.682 grams.

Volume of the ethanol obtained is 0.3304 L.

5 0

3 years ago

Can somebody please help with this question?

Leni [432]

Most of the mass of an atom is located in the (nucleus), and most of the volume is taken up by the (electron clouds).

The ones in the parenthesis are your answers.

Hope this helps!

7 0

2 years ago

Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

$ln(K)=\frac{\Delta _RG}{RT}$

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

$Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}$

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

8 0

3 years ago

Read 2 more answers