Answer:
60 m
Explanation:
After 3 seconds of travel at 20 m/s, the projectile is 3·20 = 60 meters horizontally from the cannon.
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The vertical height after 3 seconds is 0.9 m, so the straight-line distance from cannon to target is √(60^2 +0.9^2) ≈ 60.007 meters.
Answer:
They decrease trauma by allowing for a more gradual change in velocity
Explanation:
Answer:
(a) a = 2.44 m/s²
(b) s = 63.24 m
Explanation:
(a)
We will use the second equation of motion here:

where,
s = distance covered = 47 m
vi = initial speed = 0 m/s
t = time taken = 6.2 s
a = acceleration = ?
Therefore,

<u>a = 2.44 m/s²</u>
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(b)
Now, we will again use the second equation of motion for the complete length of the inclined plane:

where,
s = distance covered = ?
vi = initial speed = 0 m/s
t = time taken = 7.2 s
a = acceleration = 2.44 m/s²
Therefore,

<u>s = 63.24 m</u>
This equation is used in nuclear medicine. Nuclear medicine is the branch of medicine that deals with the use of radioactive substances in research, diagnosis, and treatment.
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In physics, this equation is generally used in the nuclear physics. </span><span>E = mc^2 gives the energy release during a nuclear reaction.</span><span>
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