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vlabodo [156]
2 years ago
5

For test 6 (150 hevy 50 light particles), what is the pressure contribution from the heavy particles?

Chemistry
1 answer:
lawyer [7]2 years ago
4 0

Answer:

The pressure contribution from the heavy particles is 17.5 atm

Explanation:

According to Dalton's law of partial pressures, if there is a mixture of gases which do not react chemically together, then the total pressure exerted by the mixture is the sum of the partial pressures of the individual gases that make up the mixture.

In the simulation:

the pressure of the 50 light particles alone was determined to be 5.9 atm, the pressure of the 150 heavy particles alone was measured to be 17.5 atm,

the total pressure of the mixture of 150 heavy and 50 light particles was measured to be 23.4 atm

Total pressure = partial pressure of Heavy particles + partial pressure of light particles

23.4 atm = partial pressure of Heavy particles + 5.9 atm

Partial pressure of Heavy particles = (23.4 - 5.9) atm

Partial pressure of Heavy particles = 17.5 atm

Therefore, the pressure contribution from the heavy particles is 17.5 atm

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How much heat is required to heat 1.6g of ice from -16c to steam at 112c?
oksian1 [2.3K]

Answer:

Total heat ≅ 49.07 kJ

Explanation:

Given that:

mass = 1.6 g = 0.016 kg

Initial temperature = - 16 ° C

final temperature = 112° C

specific heat for ice = 2.06 kJ/kgC

specific heat of water = 4.186 kJ/kgC

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To heat ice from -16 ° C to 0 ° C

Q₁ =  2.06 kJ/kgC × 0.016 kg ×  16 ° C

Q₁ =  0.52736 kJ

To melt Ice at 0° C

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To heat water from 0° C to  100° C

Q₃ = 4.186 kJ/kgC × 0.016 kg  × 100° C

Q₃ = 6.6976 kJ

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Q₅ = 2.1 kJ/kgC × 0.016 kg × 12 C

Q₅ = 0.4032 kJ

Total heat = Q₁ + Q₂ + Q₃ + Q₄  + Q₅

Total heat =  (0.52736 +  5.344 +  6.6976 + 36.096 + 0.4032) kJ

Total heat = 49.06816  kJ

Total heat ≅ 49.07 kJ

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