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tresset_1 [31]
2 years ago
12

Use for questions 1-4

Chemistry
1 answer:
Y_Kistochka [10]2 years ago
6 0

Answer: 1) 1.6 moles of HCl

2) 7.0 moles of HCl

3) 2.4 moles of hydrogen

4) 0.96 moles of HCl

Explanation:

The balanced chemical equation is:

Zn+2HCl\rightarrow ZnCl_2+H_2  

According to stoichiometry :

1 mole of Zn require = 2 moles of HCl

0.8 moles of Zn will require=\frac{2}{1}\times 0.8=1.6moles  of HCl

3.5 moles of Zn will require=\frac{2}{1}\times 3.5=7.0moles  of HCl

According to stoichiometry :

2 moles of HCl produce = 1 mole of H_2

4.8 moles of HCl will require=\frac{1}{2}\times 4.8=2.4moles  of H_2

According to stoichiometry :

1 mole of ZnCl_2 are produced by = 2 moles of HCl

0.48 moles of ZnCl_2 are produced by =\frac{2}{1}\times 0.48=0.96moles  of HCl

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Explanation:

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Read 2 more answers
A solution contains 0.036 M Cu2+ and 0.044 M Fe2+. A solution containing sulfide ions is added to selectively precipitate one of
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Answer:

The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

Explanation:

<u>Step 1: </u>Data given

The solution contains 0.036 M Cu2+ and 0.044 M Fe2+

Ksp (CuS) = 1.3 × 10-36

Ksp (FeS) = 6.3 × 10-18

Step 2:  Calculate precipitate

CuS → Cu^2+ + S^2-         Ksp= 1.3*10^-36

FeS → Fe^2+ + S^2-      Ksp= 6.3*10^-18

Calculate the minimum of amount needed to form precipitates:

Q=Ksp

<u>For copper</u>  we have:  Ksp=[Cu2+]*[S2-]

Ksp (CuS) = 1.3*10^-36 = 0.036M *[S2-]

[S2-]= 3.61*10^-35 M

<u>For Iron</u>  we have: Ksp=[Fe2+]*[S2-]

Ksp(FeS) = 6.3*10^-18 = 0.044M*[S2-]

[S2-]= 1.43*10^-16 M

CuS will form precipitates before FeS., because only 3.61*10^-35 M Sulfur Ions are needed for CuS. For FeS we need 1.43*10^-16 M Sulfur Ions which is much larger.

The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

3 0
3 years ago
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