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lyudmila [28]
3 years ago
11

How you find a unknown element (just with the atomic emission spectrum)

Chemistry
1 answer:
Sliva [168]3 years ago
5 0
Each natural element has a characteristic light spectrum that helps identify it in samples of unknown substances. Spectroscopy is the practice of examining spectra and comparing them to those of known elements. Using spectroscopy methods, scientists can identify pure substances or compounds and the elements in them.
You might be interested in
How many branches of chemistry are there .​
faltersainse [42]

Answer:

5

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0
3 years ago
Read 2 more answers
Calculate the molecular mass or formula mass (in amu) of each of the following substances: (a) BrN3 amu (b) C2H6 amu (c) NF2 amu
irakobra [83]

Answer:

Shown below

Explanation:

a) for BrN3

80+3(14)=122amu

b) forC2H6

2(12) + 6(1) = 30amu

C) for NF2

14+2(19) = 52amu

D) Al2S3

2(27) + 3(32)= 150amu

E) for Fe(NO3)3

56 + 3 [14+3(16)] =242amu

F) Mg3N2

3(24) + 2(14)= 100amu

G) for (NH4)2CO3

2[14 +4(1)] +12 +3(16)=96amu

5 0
4 years ago
Read 2 more answers
A sample of hydrogen gas was collected over water. If the total pressure
Brut [27]
It would 47.7 because you would have to both minus the number together.
7 0
3 years ago
At a pressure of 650 kpa 2.2L of hydrogen is used to fill a balloon to a final pressure of 115 kpa. What's the balloons volume?
Alborosie

Answer:

V₂ = 12.43 L

Explanation:

Given data:

Initial pressure = 650 KPa

Initial volume = 2.2 L

Final pressure = 115 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boyles law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

650 KPa ×2.2 L = 115 KPa × V₂

V₂ = 1430 KPa. L/ 115 KPa

V₂ = 12.43 L

4 0
3 years ago
If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

Hope this helps you

6 0
3 years ago
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