1.
1 answer:
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So, this is a problem where the accleration is not provided, since it is implied. The only acceleration is acceleration due to gravity (9.8 m/s)
The equation we will use for this problem is
V is the final velocity, V₀ is the initial velocity, a is the acceleration, X is the final height, and X₀ is the starting height.
We can assume that the ball starts on the ground since no height is given, so now we plug our numbers in.
We will use 0 as the final velocity, since the ball will stop moving upwards when it is the highest. We will use -9.8 since that is the acceleration due to gravity and we will use 22m/s as V₀ since that is the starting velocity.
So, the ball will go 24.69 meters up
Answer:
The distance from the North Pole to the equator is m.
Explanation:
Circumference of Earth = 40,000 km ......................(1)
Distance from the North Pole to the Equator is = 1/4th of the Circumference of Earth ...................... (2)
Let Distance from the North Pole to the Equator be d ,
the equation formed will be ,
d = 1/4 * Circumference of Earth ........(3)......... ( from equation 1 )
put the value of Circumference of Earth in equation (3),
d = 1/4 * 40,000 km
d = 10,000 km
converting km to m ,
d = 10,000 * m
d = 1 * m
The distance from the North Pole to the equator is m.
If the velocity is constant then the acceleration of the object is zero.
Thus when we apply the equation
It remains
or equivalent
Thus when we apply the equation
It remains
or equivalent
Answer:
Radius,
Explanation:
It is given that,
Magnetic field, B = 0.275 T
Kinetic energy of the electron,
Kinetic energy is given by :
v = 1037749.04 m/s
The centripetal force is balanced by the magnetic force as :
So, the radius of the circular path is . Hence, this is the required solution.