Answer:
The speed is
Explanation:
From the question we are told that
The magnetic field is
The electric field is
Generally the speed of the electron is mathematically represented as
Substituting values
Answer: M^-1 L^-3T^4A^2
Explanation:
From coloumb's law
K = q1q2 / (F × r^2)
Where;
q1, q2 = charges
k = constant (permittivity of free space)
r = distance
Charge (q) = current(A) × time(T) = TA
THEREFORE,
q1q2 = (TA) × (TA) = (TA)^2
Velocity = Distance(L) / time(T) = L/T
Acceleration = change in Velocity(L/T) / time (T)
Therefore, acceleration = LT^-2
Force(F) = Mass(M) × acceleration (LT^-2)
Force(F) = MLT^-2
Distance(r^2) = L^2
From ; K = q1q2 / (F × r^2)
K = (TA)^2 / (MLT^-2) (L^2)
K = T^2A^2M^-1L^-1T^2 L^-2
COLLEXTING LIKE TERMS
T^2+2 A^2 M^-1 L^-1-2
M^-1 L^-3T^4A^2
The cell probably needs protien and minerals (or vitamins too)
take the volume that is submerged. That's the volume of water displaced.
but the volume of submerged is different in those two
so buoyancy force is different in those two
weights are the same
probably. since the densities* are different.
In question it says wights are the same and diffferent volumes
so it seems that the one with more density should have a lower buyonacy force
but you said that when an object floats the buoyancy force equals weight,so since both objects have the same weight,then buoynacy force should be equal in those two
The more dense object will float with a greater percentage of its volume immersed, not less.
2) If they have the same MASS, the more dense one will have less VOLUME
Answer:
0.60 N, towards the centre of the circle
Explanation:
The tension in the string acts as centripetal force to keep the ball in uniform circular motion. So we can write:
(1)
where
T is the tension
m = 0.015 kg is the mass of the ball
is the angular speed
r = 0.50 m is the radius of the circle
We know that the period of the ball is T = 0.70 s, so we can find the angular speed:
And by substituting into (1), we find the tension in the string:
And in an uniform circular motion, the centripetal force always points towards the centre of the circle, so in this case the tension points towards the centre of the circle.