<h2>
Answer </h2>
The answer to this question is <u>407.5 g</u>
<h2>
Explanation</h2>
- The density of the substance = 1.63 g/ml
- The volum of the substance = 0.25 L
- Mass of the substance = ? (Determined)
We know that

So, 0.25 L will be equal to 250 ml. ( Unit must be same)
Formula




Se, mass of the substance is 407.5 g
Answer:Distance=6.67 (rounded)
Explanation: Work = Force x Distance.
100 Joules of work= force of 15 N x Distance (?)
The work equation given above can be rearranged to find force or distance if the other variables are known:
Distance=Work / force
Distance=100Joules/15 N
Distance=6.67 (rounded)
Answer:
2. F g decreases to 1/9
Explanation:
The formula for calculating the Force of gravity between two masses separated by a distance is expressed as;
F = GMm/d² ... 1
If the distance is tripled, the new force will be;
F1 = GMm/(3d)²
F1 = GMm/9d² ... 2
Divide equation 1 by 2
F/F1 = GMm/d²÷GMm/9d²
F/F1 = GMm/d²×9d²/GMm
F/F1 = 1 * 9
F = 9F1
F1 = 1/9 F
<em>This means that the new force decreases to 1/9</em>
Answer:
The two objects will collide with the same position vector for all three components at exactly t = 4 s
Explanation:
For two particles starting out at the same time to collide, their position Vector's at the time of collision must be exactly the same.
So, at the collision point, position vector of object 1 is equated to that of object 2.
r₁ = (t², 13t-36, t²)
r₂ = (7t-12, t², 5t-4)
At he point of collision
t² = 7t - 12
t² - 7t + 12 = 0
t² - 4t - 3t + 12 = 0
t(t - 4) - 3(t - 4) = 0
t = 3s or t = 4s
13t - 36 = t²
t² - 13t + 36 = 0
t² - 4t - 9t + 36 = 0
t(t - 4) - 9(t - 4) = 0
t = 9s or 4s
t² = 5t - 4
t² - 5t + 4 = 0
t² - 4t - t + 4 = 0
t(t - 4) - 1(t - 4) = 0
t = 1s or t = 4s
The three components intersect at other times, but at t = 4s, they all intersect at the same time! Meaning that, at this point the two objects are at the same place with the same position vector at that time.
Answer:
0.1 L
Explanation:
From the question given above, we obtained the following data:
Initial volume (V₁) = 0.05 L
Initial Pressure (P₁) = 207 KPa
Final pressure (P₂) = 101 KPa
Final volume (V₂) =?
We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
207 × 0.05 = 101 × V₂
10.35 = 101 × V₂
Divide both side by 101
V₂ = 10.35 / 101
V₂ = 0.1 L
Thus, the new volume of the gas is 0.1 L