Answer:
The rod`s charge must be positive, because the gravity force is pointing downwards and the electrostatic force must be pointing upwards (in order to balance the gravity force)
The charge is q_2 = 1.667 times 10^(-7) C
Explanation:
F_e = F_g
where F_g = m g and F_e= (1/4 pi e_0)*(q_1*q_2)/d^2,
please see the file attached for more details.
I think it’s D which is the stomach if not I can get you someone that can help you
<span>A center-seeking force related to acceleration is centripetal force. The answer is letter A. The rest of the choices do not answer the question above.</span>
Answer:
The velocity of the ball when its hit the ground will be 54.22 m/sec
Explanation:
We have given height from which ball is dropped h = 150 m
Acceleration due to gravity 
As the ball is dropped so initial velocity will be zero so u = 0 m/sec
According to third equation of motion we know that 


So the velocity of the ball when its hit the ground will be 54.22 m/sec
Answer:v=0.0485m^3/kg
Explanation:
PV=MRT
PV/M=RT
Pv=RT
P=8.5mpa= 850Kpa
T= 139K
v= RT/P
0.2968*139/850
v=0.0485m3/kg
Error
0.0485-0.002002/0.0485*100%
95%