Solution :
In the field of chemistry, the cationic polymerization is a kind of the chain growth polymerization where the cation initiator transfers the charge to the monomer and makes it more reactive. This kind of polymerization reaction is very sensitive to the temperature. With increase in temperature, the molecular weight as well as the reaction rate decreases rapidly.
Thus in the cationic polymerization of the 3,3-dimethyl-1-butene, the carbonation intermediate is formed and it rearranges itself. The attack o the 2nd alkene ca take place both the carbonations, so that random copolymer is formed.
Answer:
Explanation:
HCl + NaOH = NaCl + H₂O.
1 mole 1 mole 1 mole 1 mole
6.93 g of hydrochloric acid = 6.93 / 36.5 = .189 mole of HCl
2.4 g of NaOH = 2.4 / 40 = .06 mole of NaOH
NaOH is in short supply so it is the limiting reagent .
1 mole of NaOH reacts with 1 mole of HCl to give 1 mole of Water
.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water
Water formed = .06 mole
= .06 x 18 = 1.08 g
= 1.1 g
Answer:
https://socratic.org/answers/220339
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Explanation:
Answer:
b.Rearrange the two equations to make each variable the focus (you will end up with three variations for each equation).
HNO₃ + H₂S → S + NO + H₂<span>O
Assign Oxidation Number:
L.H.S R.H.S
N in HNO</span>₃ = +5 +2 = N in NO
S in H₂S = -2 0 = S in S
Write Half cell Reactions:
Reduction Reaction:
3e⁻ + HNO₃ → NO -------(1)
Oxidation Reaction:
H₂S → S + 2e⁻ -------(2)
Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons.
6e⁻ + 2 HNO₃ → 2 NO
3 H₂S → 3 S + 6e⁻
Cancel e⁻s,
______________________________
2 HNO₃ + 3 H₂S → 2 NO + 3 S + H₂O
Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.
2 HNO₃ + 3 H₂S → 2 NO + 3 S + 4H₂O
