During which of the following phases of the moon do we see the left half of the moon as lit?
1 answer:
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Answer:
The ration of molar concentration is "2.5".
Explanation:
The given values are:
Average density of salt water,
=
Net pressure,
=
Increase in pressure,
=
Now,
The under water pressure will be:
=
=
=
=
hence,
The ratio will be:
=
or,
=
=
=
Answer:
0.4 M
Explanation:
The process that takes place in an aqueous K₂HPO₄ solution is:
- K₂HPO₄ → 2K⁺ + HPO₄⁻²
First we <u>calculate how many K₂HPO₄ moles are there in 200 mL of a 0.2 M solution</u>:
- 200 mL * 0.2 M = 40 mmol K₂HPO₄
Then we <u>convert K₂HPO₄ moles into K⁺ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction above:
- 40 mmol K₂HPO₄ *
= 80 mmol K⁺
Finally we <em>divide the number of K⁺ moles by the volume</em>, to <u>calculate the molarity</u>:
- 80 mmol K⁺ / 200 mL = 0.4 M
Answer:
8. the answer is B.
9. the answer is A.
Explanation:
Hello!
8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.
9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:
Thus, the answer is this case is A.
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