Question

Which of the following has a polar covalent bond? b. Which of the following has a bond closest to the ionic end of the bond spectrum? CH3NH2 CH3CH3 CH3OH

Answer 1

Answer:

a. CH₃OH.

b. CH₃F

Explanation:

Hello,

b. In this case, the polar covalent bond is in the O-H bond in the CH₃OH as the difference between the oxygen's and hydrogen's electronegativities is:

$\Delta E=3.44-2.2=1.24$

Which is eligible for a polar covalent bond.

b. However, since CH₃F is not in the list, it is the compound having a bond closest to the ionic end of the bond spectrum since fluorine is highly electronegative, therefore, it creates a dipole moment in the molecule which provide such feature.

Best regards.

Answer 2

Explanation:

Polar covalent bonding is the type of the chemical bond in which the pair of the electrons is unequally shared between the two atoms. As a result, the atom with higher value of electronegativity acquires a slightly negative charge and the atom with lower value of electronegativity acquires a slightly positive charge.

In the molecule of $CH_3NH_2$, the bond which is closest to ionic end of bond spectrum is N-H bond because the nitrogen atom is more electronegative than hydrogen and is ionic in nature.

In the molecule of $CH_3CH_3$, the bond which is closest to ionic end of bond spectrum is no one because there is not much difference between carbon and hydrogen for the bond to be said as ionic.

In the molecule of $CH_3OH$, the bond which is closest to ionic end of bond spectrum is O-H bond because the oxygen atom is more electronegative than hydrogen and is ionic in nature.