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Art [367]
3 years ago
15

Calculate the mass (in g) of solute needed to prepare a solution with the given concentration and volume.

Chemistry
1 answer:
sweet [91]3 years ago
3 0

Answer:

1. 35g NaCl.

2. 234g sugar.

3. 0.506L of concentrated nitric acid are needed.

4. 1.67L of 9.0M copper (II) sulfate are needed

Explanation:

Molarity is defined as the ratio between moles of solute and the volume of the solution.

1. 1.00L * (0.60mol / L) = 0.60 moles NaCl are dissolved

To convert moles to mass we must use its molar mass:

0.60mol NaCl * (58.44g/mol) =

35g NaCl

2. 2L * (0.342mol / L) = 0.684 moles Sugar = moles sucrose

0.684 mol * (342.30g / mol) = 234g sugar

3. 4L of a 2.0M are:

4L * (2.0mol/L) = 8moles

8mol * (1L / 15.8mol) = 0.506L of concentrated nitric acid are needed

4. 3.0L  * (5.0 mol / L) = 15.0 moles copper (II) sulfate.

15.0mol * (1L / 9.0mol) = 1.67L of 9.0M copper (II) sulfate are needed

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A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at
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Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, heat_{absorbed}=heat_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 45 g

m_2 = mass of coffee = 180 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 85^oC

c_1 = specific heat of aluminium = 0.80J/g^oC

c_2 = specific heat of coffee= 4.186 J/g^oC

Putting all the values in equation 1, we get:

45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]

T_{final}=80.30^oC

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

8 0
3 years ago
d) A short ton of coal holds about 2.24 x 107 J of energy and costs about $56.45 per short ton. How many Joules of energy in the
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Answer:

396811.337 J

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The energy related to the short ton of coal = 2.24\times 10^{7}\ J

Thus, As according to the question,

$56.45 of coal have 2.24\times 10^{7}\ J of energy.

$1 of coal have \frac{2.24\times 10^{7}}{56.45}\ J of energy.

<u>The amount of energy = 396811.337 J</u>

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3 years ago
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