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vagabundo [1.1K]
3 years ago
11

This human cause process is called ____ and can drastically increase the natural process _____​

Chemistry
2 answers:
allsm [11]3 years ago
5 0

Answer:

Deforestation, Erosion

Explanation:

Study Island Lesson

bekas [8.4K]3 years ago
3 0

Answer:

Global warming and the greenhouse effect.

Explanation:

people believe that global warming is something that is real and it isn't.

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Which of the following is NOT an example of a molecule <br> A: H2O2<br> B:NCI3<br> C:F<br> D:O3
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C. F because it's an atom not a molecule

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An atom of an element has 5 electrons in L-shell.
pishuonlain [190]
I dont know your question but that is true
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What did organizing information on the periodic table reveal?
Natalka [10]

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The groupings of elements in the periodic table reveal various trends, present in groups such as the alkali metals and noble gases, or the lanthanides and actinides. The periodic table can be used to find information on elements or predict the properties of as-of-yet undiscovered elements.

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A hot toluene stream, which has mass flow rate of 8.0 kg/min, is cooled by cooling water in a cocurrent heat exchanger; its temp
Alex Ar [27]

Complete Question  

The complete question is shown on the first question

Answer:

a) The duty of the heat exchanger is given as 6.8658 KJ /sec

b) The temperature of the water leaving the exchanger is TOUT = 29.84 ⁰C

c) The log mean difference is given as TZ = 47.317 ⁰ C

d) the UA value is UA = 145.10

Explanation:

The explanation is uploaded on the first and second ,third and fourth image

3 0
3 years ago
A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?
uranmaximum [27]

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

  • Hafnium = 55.7% = 55.7g
  • Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

  • Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
  • Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

  • Hafnium = 0.312 ÷ 0.312 = 1
  • Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

#SPJ1

7 0
1 year ago
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