42.9°
Explanation:
Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:


Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at
Solving for the angle, we get

or

![\;\;\;= \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right]](https://tex.z-dn.net/?f=%5C%3B%5C%3B%5C%3B%3D%20%20%5Csin%5E%7B-1%7D%5Cleft%5B%5Cdfrac%7B34%5C%3A%5Ctext%7BN%7D%7D%7B%285.1%5C%3A%5Ctext%7Bkg%7D%29%289.8%5C%3A%5Ctext%7Bm%2Fs%7D%5E2%29%7D%5Cright%5D)

Acceleration = Force \ mass
0,375N/0,60kg=0.6ms-2
Because it eats plants and animals.
9514 1404 393
Answer:
- moderate low: 82
- moderate high: 112.75
- vigorous low: 123
- vigorous high: 174.25
Explanation:
When calculations are repetitive, I find it convenient to use a calculator that can work with tables.
The PMHR is (220 -15) = 205.
Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = <u> 82 </u> bpm
The other rates are shown in the attached table. They are computed the same way.
Answer: The 1 kg fragment will have three times the speed of the 3kg fragment.
Explanation:Here for the bomb, its chemical energy gets converted into the mechanical energy.
According to the law of conservation of momentum, the two bodies will have equal momentum and to satisfy this condition the lighter mass will have the higher velocity.
∵ momentum, p = mass × velocity
∴The 1 kg fragment will have three times the speed of the 3kg fragment.