Answer: 1. 3.23 m
2. 32.4
3. B adding solvent and C removing solute
Explanation:
1. Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent
where,
n = moles of solute
= weight of solvent
Now put all the given values in the formula of molality, we get
2. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
Therefore, the moles of 
is 32.4
3. Molarity can be decreased by decreasing the moles of solute and by increasing the volume of solution.
Thus adding solvent and removing solute will decrease the molarity.
An acid is a compound which will give H+ ions or H3O^+ ions
the reaction will be
![[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}](https://tex.z-dn.net/?f=%5BMn%28H_%7B2%7DO%20%29_%7B6%7D%20%5E%7B%2B3%7D%20%2BH_%7B2%7DO%20--%3E%20%5BMnOH%28H_%7B2%7DO%29_%7B5%7D%5D%5E%7B%2B2%7D%20%2B%20H_%7B3%7DO%5E%7B%2B%7D)
Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid
Answer:
Yes. The volume would be 1/4 of the initial volume.
Explanation:
At constant temperature, the pressure of a gas is inversely proportional to the volume of the gas. Hence;
P1V1 = P2V2
<em>where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.</em>
If the pressure of a gas is quadrupled;
P2 = 4P1, the equation becomes
P1V1 = 4P1 x V2
Making V2 the subject:
V2 = P1V1/4P1
V2 = V1/4
<em>This means that the volume would change by being reduced to </em><em>1/4 </em><em>of the initial volume.</em>
16: solar energy, 17: glucose, 18: heat, 19: atp
