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zheka24 [161]
3 years ago
13

A car company uses the table below to show customers the appropriate amount of gas used when a car has been driven a certain num

ber of miles.
if the car always uses the same amount of gas each time, how many gallons of gas would be needed to travel 480 miles?

A. 20

B. 24

C. 33

D. 39

​

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

Answer:

B. 24

Step-by-step explanation:

  • This is a simple ratio.
  • If 1 mile = 0.05 gallons of gasoline, then 480 miles = 24 gallons of gasoline!
aleksandrvk [35]3 years ago
7 0
Is B.24 because 120 divided by 5 is 20 and 300 divided by 16 is 20 etc. So 480 divided by 20 is 24 so the answer is 24 gallons of gas
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2.14x - 42.9 for x = 22.4 ?<br> A. -18.36<br> B. 5.026<br> C. 47.939<br> D. 90.839
Fynjy0 [20]

Answer:

Step-by-step explanation:

Your answer would be B., because you would multiply

2.14 x  22.4   =

47.939  

then you will subtract that by 42.9

47.939 - 42.9 =  

5.026

7 0
4 years ago
I need help with this any help will be appreciated
Mars2501 [29]
Are you trying to solve for x and y?

y=2x+1; x+2y=17
sub in one variable in the other equation.
x+2(2x+1)=17
x+4x+2=17
5x=15
x=3

now that you have x value, plug into the original equation to find y and check with the other. 
y=2(3)+1 = 7
x+2y=17 = 3 + 2(7) = 17 ; 17=17 
7 0
3 years ago
Fill in the missing term and select the missing description. Simplify any fractions.
mina [271]

Answer:

t = 18/2

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6 0
3 years ago
HELPPPPPP PLEASEEEEee 34 + 2 ⋅ 5 = ____. (Input whole numbers only.) (1 point)
yaroslaw [1]
The answer is 44
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5 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
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