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alexandr1967 [171]
3 years ago
14

What are two consecutive integers, such that five times the smaller minus three times the larger is 51? What is the smallest int

eger?
Mathematics
1 answer:
Xelga [282]3 years ago
3 0
<h3>Answer:   27</h3>

===============================================

Work Shown:

x = smaller integer

x+1 = larger integer

x and x+1 are consecutive integers since the larger follows right after the smaller

5*(smaller) - 3*(larger) = 51

5*(x) - 3*(x+1) = 51

5x - 3x - 3 = 51

2x - 3 = 51

2x = 51+3

2x = 54

x = 54/2

x = 27

x+1 = 27+1 = 28

The two consecutive integers are 27 and 28.

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The formula for calculating the nth term of a geometric sequence is expressed as:

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