What are two consecutive integers, such that five times the smaller minus three times the larger is 51? What is the smallest int
eger?
1 answer:
<h3>
Answer: 27</h3>
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Work Shown:
x = smaller integer
x+1 = larger integer
x and x+1 are consecutive integers since the larger follows right after the smaller
5*(smaller) - 3*(larger) = 51
5*(x) - 3*(x+1) = 51
5x - 3x - 3 = 51
2x - 3 = 51
2x = 51+3
2x = 54
x = 54/2
x = 27
x+1 = 27+1 = 28
The two consecutive integers are 27 and 28.
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