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3 years ago

Which one of the following electron transitions does not correspond to an absorbtion of a quanta of light?

Chemistry

1 answer:

ziro4ka [17]3 years ago

8 0

N = 4 to n = 3 is the right answer, so it' none of the above

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The following reaction is a fusion/fission reaction.<br><br>- Equation is attached as an image -

vagabundo [1.1K]

Must be the same circle as the flipped equatio times they divided numbers of

8 0

3 years ago

A compound is 79.94g carbon, 26.82g hydrogen, and 93.24g nitrogen. What is the empirical formula?

Pani-rosa [81]

Answer:

i dont know

Explanation:

sorry

5 0

3 years ago

In TEN complete sentences, describe how the LAW OF CONSERVATION applies to the stuff YOU OWN. For example: In real life, can new

satela [25.4K]

Answer:

Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and type of atoms after the chemical change as were present before the chemical change.

Explanation:

The atoms that make up your body were produced inside a star and have ... I read once that atoms get recycled so much through the planet that each of ... from William Shakespeare, but I do know this: All of us come from stars. ... If you have gold fillings in your teeth, those atoms came from a star explosion.

6 0

2 years ago

Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit

rosijanka [135]

Explanation:

The relation between $K_a\&K_b$ is given by :

$K_w=K_a\times K_b$

Where :

$K_w=1\times 10^{-14}$ = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = $K_{a1}=1.4\times 10^{-2}$

The value of $K_{b1}$ :

$1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}$

The value of the second ionization constant of sodium sulfite = $K_{a2}=6.3\times 10^{-8}$

The value of $K_{b2}$ :

$1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}$

3 0

3 years ago

Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged

Nesterboy [21]

Answer: Boyle's law

Explanation: It states that pressure of a gas is inversely proportional to the volume of a gas at constant temperature.

$P$ ∝ $\frac{1}{V}$ at constant temperature

or If the pressure of gas is decreased, the volume increases if the temperature is unchanged and If the pressure of gas is increased, the volume decreases if the temperature is unchanged.

$P_1V_1=P_2V_2$

3 0

3 years ago

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