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3 years ago

Calculate the number of molecules in 6.00 moles h2s?.

2 answers:

6 0

Use the equation: Nm = M x Av
Nm = Moles x Avogadro constant
Nm = 6 x 6.02x10²³
Nm = 3.612x10²⁴

so in six moles of H2S there are 3.612x10²⁴ molecules

hope that helps

LenKa [72]3 years ago

5 0

To calculate the number of molecules in 6.00 moles of hydrogen sulfide, H2S, the equivalence factor used is Avogadro's number equal to (6.022 x 10^23 molecules/mole). The answer is 6.00 moles of hydrogen sulfide * (6.022 x 10^23 molecules/mole) equal to 3.61 x10^24 molecules.

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A scientist studies the DNA of three different species. The DNA from species A is more similar to DNA from species B than DNA fr

rewona [7]

DNA A and B are probably the most closely related because cells get DNA from the parent cells therefor similar DNA comes from relatives.

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3 years ago

PLEASE HELP

charle [14.2K]

Answer: The statement, average kinetic energy of the gas particles is greater in container A because its particles move faster is correct.

Explanation:

Kinetic energy is the energy obtained due to the motion of an object or substance.

$K.E = \frac{3}{2}kT$

where,

T = temperature

This means that kinetic energy is directly proportional to temperature.

So, when heat is provided to container A then its molecules will start to move rapidly from one place to another which will cause more collisions between the atoms.

Hence, average kinetic energy will be more in container A.

Whereas container B is placed at room temperature which is low than that in container A. So, molecules in container B will move at almost same speed and therefore, specific collisions will be there. So, average kinetic energy in container B will be less than that in container A.

Thus, we can conclude that the statement, average kinetic energy of the gas particles is greater in container A because its particles move faster is correct.

8 0

3 years ago

Propose a 3-step reaction for the conversion of cyclopentene to propanedioic acid

Gnom [1K]

I
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6 0

3 years ago

How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3

8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

$\frac{3}{1} =\frac{y}{0.02256} \\$

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0

3 years ago

How many hours will it take for the concentration of methyl isonitrile to drop to 15.0 % of its initial value?

SpyIntel [72]

Answer:

The concentration of methyl isonitrile will become 15% of the initial value after 10.31 hrs.

Explanation:

As the data the rate constant is not given in this description, However from observing the complete question the rate constant is given as a rate constant of 5.11x10-5s-1 at 472k .

Now the ratio of two concentrations is given as

$ln (\frac{C}{C_0})=-kt$

Here C/C_0 is the ratio of concentration which is given as 15% or 0.15.

k is the rate constant which is given as $5.11 \times 10^{-5} \, s^{-1}$

So time t is given as

$ln (\frac{C}{C_0})=-kt\\ln(0.15)=-5.11 \times 10^{-5} \times t\\t=\frac{ln(0.15)}{-5.11 \times 10^{-5} }\\t=37125.6 s\\t=37125.6/3600 \\t= 10.31 \, hrs$

So the concentration will become 15% of the initial value after 10.31 hrs.

7 0

3 years ago

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