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kiruha [24]
3 years ago
12

Calculate the number of molecules in 6.00 moles h2s?.

Chemistry
2 answers:
leonid [27]3 years ago
6 0
Use the equation: Nm = M x Av
                             Nm = Moles x Avogadro constant
                             Nm = 6 x 6.02x10²³
                             Nm = <span>3.612x10</span>²⁴

so in six moles of H2S there are 3.612x10²⁴ molecules

hope that helps  
LenKa [72]3 years ago
5 0
To calculate the number of molecules in <span>6.00 moles of hydrogen sulfide, H2S, the equivalence factor used is Avogadro's number equal to (6.022 x 10^23 molecules/mole). The answer is 6</span>.00 moles of hydrogen sulfide * <span>(6.022 x 10^23 molecules/mole) equal to 3.61 x10^24 molecules.</span>
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Which of the following is not equal to 42.7 millimeters?
Stella [2.4K]

The answer is: C. 0.00427 m.

A) 1 km = 1000000 mm.

d = 0.0000427 km · 1000000 mm/km.

d = 47.7 mm.

B) 1 hm = 100000 mm.

d = 0.000427 hm · 100000 mm/hm.

d = 42.7 mm.

C) 1 m = 1000 mm.

d = 0.00427 m · 1000 mm/m.

d = 4.27 mm.

D) 1 cm = 10 mm.

d = 4.27 cm · 10 mm/cm.

d = 42.7 mm.

Millimeter (abbreviated: mm, a thousandth part of metar) is an unit of distance in the metric system.

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Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of chromium(III) bromide and pota
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Explanation:

An ionic equation will be the one in which all the participating species will be present as ions.

The given reaction will be as follows.

     CrBr_{3} + K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + KBr

Balancing this equation by multiplying CrBr_{3} by 2 and K_{2}CO_{3} by 3 on reactant side. Whereas multiply KBr by 6 on product side.

      2CrBr_{3} + 3K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6KBr

Hence, the net ionic equation will be as follows.

       2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) + 6K^{+} + 6Br^{-} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6K^{+} + 6Br^{-}

As both K^{+} and Br^{-} are spectator ions. Hence, the net ionic equation will be as follows.

     2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) \rightarrow Cr_{2}(CO_{3})_{3}(s)  

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