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Ray Of Light [21]
3 years ago
12

Give examples of factors or criteria often used to determine higher wages for a particular job

Physics
2 answers:
marshall27 [118]3 years ago
5 0
-- the applicant's previous experience at similar jobs;
-- the color of the applicant's hair;
-- the applicant's grammar and vocabulary;
-- where the applicant went to school;
-- the shirt the applicant wears to the job interview;
-- the applicant's favorite football team;
-- the applicant's self-confidence;
Dmitry [639]3 years ago
5 0

Answer:

(a) Worker’s capacity and age. As older a worker is, it is supposed he will have more experience.

(b) Hazards involved in work. As dangerous the job is, it is higher paid.

(c) The prevailing wage in the community. The prevailing or mean salary for a job market is a base to determine some high paid wage rates.

Reference: Chand, Smriti. “7 Factors to Consider for Determining Wage and Salary Structure of Workers.” Your Article Library, 4 Feb. 2014,

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xenn [34]

Answer: 4 herz is the answer!

Explanation:

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The advantage of nuclear power include the low production of air pollution and the fact that is not produce a toxic waste materi
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Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

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B: heat is transferred as thermal energy by the interaction of moving particles
6 0
3 years ago
A bug flying horizontally at 0.65 m/s collides and sticks to the end of a uniform stick hanging vertically. After the impact, th
irina [24]

The angular momentum is defined as,

L=I\omega

Acording to this text we know for conservation of angular momentum that

L_i=L_f

Where L_iis initial momentum

L_f is the final momentum

How there is a difference between the stick mass and the bug mass, we define that

Mass of the bug= m

Mass of the stick=10m

At the point 0 we have that,

L_i=mvl

Where l is the lenght of the stick which is also the perpendicular distance of the bug's velocity

vector from the point of reference (O), and ve is the velocity

At the end with the collition we have

L_f=(I_b+I_s)\omega

Substituting

L_f=(ml^2+\frac{10ml^2}{3})\omega

L_f=\frac{13}{10}ml^2w

m(0.65)l=\frac{13}{10}ml^2 \omega

\omega=\frac{1}{2l}

Applying conservative energy equation we have

\frac{1}{2}(I_b+I_s)\omega^2=mgh+10mgh'

\frac{1}{2}(ml^2+\frac{10ml^2}{3})(\frac{1}{2l})^2=mg(l-lcos\theta)+\frac{10}{2}mg(l-lcos\theta)

Replacing the values and solving

l=\frac{13}{0.54g}

Substituting

l=\frac{13}{0.54(9.8)}

l=2.45cm

7 0
3 years ago
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