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3 years ago

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

Physics

2 answers:

pishuonlain [190]3 years ago

5 0

Answer: That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

ZanzabumX [31]3 years ago

3 0

The most dense thing inside the column is the little star. It's pink, and it's resting on the bottom of the cylinder.

The red part under the star is the solid base that the cylinder is standing in. It's probably wood or plastic, it's not free to move, and it's not involved in the experiment.

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A student uses a spring to launch a marble vertically in the air. The mass of the marble is

Fed [463]

Answer:

the maximum height reached by the marble is 11.84 m.

Explanation:

Given;

mass of the marble, m = 0.02 kg

extension of the string, x = 0.08 m

force applied to the string, F = 58 N

Apply the principle of conservation of energy;

elastic potential energy = gravitational potential energy

¹/₂fx = mgh

$h = \frac{Fx}{2mg} \\\\h = \frac{58 \ \times \ 0.08}{2 \ \times \ 0.02 \ \times \ 9.8} \\\\h = 11.84 \ m$

Therefore, the maximum height reached by the marble is 11.84 m.

5 0

3 years ago

What is the magnetic force on a proton that is moving at 4.5 x 10^7 m/s to the right through a magnetic field that is 1.6 T and

Agata [3.3K]

The magnetic force on a charged particle is given as: F = qvBsinФ
B is the magnetic field.
q is the charge on the particle.
v is the velocity of the charged particle.
Ф is the angle between magnetic field (B) & the velocity of charge (v).

⇒ F = qvb sin Ф

Here, Ф = 90 degree.
and sin 90 = 1
Putting the values in the equation, we get,

F = 1.6 x 10^-19 C × 4.5 × 10^7 m/s × 1.6 T
= 11.52 × 10^-12N
= 1.2 x 10^-11 N up

4 0

3 years ago

an optician uses a plane mirror to help him. suppse a patient sits in a chair 2.5m away from him. He views the image of a chart

viva [34]

Answer:

I think 75 m

Explanation:

tell if it was correct

5 0

3 years ago

In an electron dot diagram (Lewis Structure) of aluminum. (A1), how many dots should be drawn around the element's symbol? why?

Leni [432]

3 of the valence electrons.

7 0

3 years ago

Ear "popping" is an unpleasant phenomenon sometimes experienced when a change in pressure occurs, for example,in an airplane. If

marshall27 [118]

Answer:

H = 0.00058m = 0.58mm of Mercury

h = 160m for popping at 8000m

Explanation:

Air density decreases with altitude (increasing height).

At sea level air density = 1.22kg/m^3

while at 3000m above it is approximately 0.8 kg/m^3

ASSUMPTION:

we neglect the change in density across 100m vertically

density of mercury = 13600kg/m ^3

we equate the pressure for mercury and air

AIR(pgh) = Mercury(pgh)

0.8 * g * 100 = 13600 * g * H

H = 0.00058m = 0.58mm of Mercury

At even farther heights, the air density further drops

at 8000m above it is 0.52kg/ m^3 (source:https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html)

***for the ear to pop again, it has to experience same change in pressure as of at 3000m

Change in P for AIR at 3000m = Change in P for AIR at 8000m

ASSUMPTION : gravitational acceleration does not change with altitude

pgh = pgh

0.8 * g * 100 = .5 * g *h

h = 160m

3 0

4 years ago