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GenaCL600 [577]
3 years ago
6

H 2 + O 2 H 2 O How many moles of H 2 O are produced from 3 moles of oxygen ?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

8

I believe 2 moles are produced :/

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What occurs to the electromagnetic radiation from the sun enters earths atmosphere
Ilya [14]

Answer:

When electromagnetic radiations enter earth surface , it passes through several layers of our atmosphere in meantime some raditions get reflected back and some reaches to us .

7 0
3 years ago
Read 2 more answers
I need some help with a long chemistry problem. Anything is appreciated!
Mkey [24]

Answer:

The CSI is wrong.  

Explanation:

1. Find the volume of the pool

The formula for the volume of a cylinder is  V = πr²h .

D = 12 m; h = 10 m

r = D/2 = (12 m/2) = 6.0 m

V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³

= 1.1. × 10⁶ L

2. Calculate the moles of OH⁻

n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻                                                                                                                                                                                                                                                                                                                              

3. Calculate the moles of acetic acid needed for neutralization

HA + OH⁻ ⟶ A⁻ + H₂O

The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.

4. Calculate the actual moles of acetic acid

You have four 5 L jugs of acetic acid pH 2 .

Volume = 20 L

[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹

(a) Set up an ICE table

                      HA + H₂O ⇌ A⁻  + H₃O⁺

I/mol·L⁻¹:          c                   0         0

I/mol·L⁻¹:     - 0.01             +0.01    +0.01

I/mol·L⁻¹:    c - 0.01             0.01     0.01

K_{\text{a}} = \dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}  = 1.76 \times 10^{-5}

(b) Calculate the concentration of acetic acid

\begin{array}{rcl}\dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}& = & 1.76 \times 10^{-5}\\\\\dfrac{0.01\times 0.01}{c}& = & 1.76 \times 10^{-5}\\\\1 \times 10^{-4} & = & 1.76 \times 10^{-5}c\\c & = & \dfrac{1 \times 10^{-4}}{1.76 \times 10^{-5}}\\\\ & = & \text{6 mol/L}\\\end{array}

The concentration of the acetic acid is 6 mol·L⁻¹

(c) Calculate the moles of acetic acid

n = \text{20 L} \times \dfrac{\text{6 mol}}{\text{1 L}} = \textbf{100 mol}

You have 100 mol of acetic acid.

The CSI is wrong.

You don't have enough acetic acid to neutralize the pool.

8 0
4 years ago
2. True False) When you are looking at a tissue under the microscope, the only tissue you will ever see is!
emmainna [20.7K]

Answer:

true

Explanation:

8 0
3 years ago
) The volume of a balloon was 50,200 litres. If the temperature
Rudiy27

Answer:

1943.1 moles

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 50200 L

Temperature (T) = 25 °C

Pressure (P) = 720 mmHg

Number of mole (n) of H₂ =?

Next, we shall convert 25 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 25 °C

Temperature (T) = 25 °C + 273

Temperature (T) = 298 K

Next, we shall convert 720 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

720 mmHg = 720 mmHg × 1 atm / 760 mmHg

720 mmHg = 0.947 atm

Thus, 720 mmHg is equivalent to 0.947 atm

Finally, we shall determine number of mole of Hydrogen gas, H₂, needed to fill the balloon as follow:

Volume (V) = 50200 L

Temperature (T) = 298 K

Pressure (P) = 0.947 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) of H₂ =?

PV = nRT

0.947 × 50200 = n × 0.0821 × 298

47539.4 = n × 24.4658

Divide both side by 24.4658

n = 47539.4 / 24.4658

n = 1943.1 moles

5 0
3 years ago
1) How much energy would be required to melt 15.0 g of ice at 0°C?
DerKrebs [107]

Answer:

5010J

Explanation:

The following data were obtained from the question:

Mass (m) = 15g

Heat of fusion (ΔHf) = 334J/g

Heat required (Q) =..?

The heat energy required to melt the ice can be obtained as follow:

Q = m·ΔHf

Q = 15 x 334

Q = 5010J

Therefore, the heat energy required to melt the ice is 5010J.

8 0
3 years ago
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