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MAVERICK [17]
3 years ago
7

A tennis ball with a speed of 15.7 m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the oppo

site direction with a speed of 14.444 m/s. If the ball is in contact with the wall for 0.0099 s, what is the average acceleration of the ball while it is in contact with the wall? Take "toward the wall" to be the positive direction. Answer in units of m/s 2 .
Physics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

-3044.848m/s^2

Explanation:

Initial velocity = 15.7 m/s (u)

Final velocity = -14.444 m/s (v) velocity after striking moving opposite direction.

Time = 0.0099 s

Average acceleration :

change in velocity/ total time

= V - U/t

= -14.444 m/s - 15.7 m/s/0.0099 s

= -30.144/0.0099 s

= -3044.848m/s^2

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A force can give a certain mass a certain acceleration. if i double the force and double the mass, the acceleration of this obje
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<h3>What does acceleration mean ?</h3><h3 />

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Learn more about Acceleration here:

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6 0
1 year ago
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Reika [66]

Answer:

t=750s

Explanation:

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x_f is the same for both cars when the second one catches up with the first. If we take as reference point the initial position of the second car, we have:

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We have x_f_1=x_f_2. Thus, solving for t:

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Answer:

d. Not enough information is given to answer this question.

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