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liubo4ka [24]
3 years ago
14

Qué fuerza neta actúa sobre una caja que se desliza cuando ejerces sobre ella una fuerza de 110 N y la fricción entre la caja y

el suelo es 100 N?
Physics
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

if this is translated ill answer it

Explanation:

sorry i cant reed this language

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An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),
Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane h=6\ miles

When Airplane is s=10\ miles away

Distance is changing at the rate of \frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph

From diagram we can write as

h^2+x^2=s^2

differentiate above equation w.r.t time

2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}

as altitude is not changing therefore \frac{\mathrm{d} h}{\mathrm{d} t}=0

0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}

at s=10\ miles\ and\ h=6\ miles

substitute the value we get x=\sqrt{10^2-6^2}=8\ miles

8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290

\frac{\mathrm{d} x}{\mathrm{d} t}=362.5\ mph

5 0
3 years ago
What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: PE = mgh)
Lisa [10]

Answer:

The answer would be 735J

Explanation:

PE=mgh

=(mass)(force of gravity)(height)

=(25kg)(9.8m/s^2)(3m)

=735J

8 0
3 years ago
Read 2 more answers
Change of 5000 c flows through a circuit in one hour. what is the current intensity?​
AleksandrR [38]

Answer:

I = 1.38 A

Explanation:

Given that,

Charge, q = 5000 C

Time, t = 1 hour = 3600 s

We need to find the current intensity. The current intensity is equal to the electric charge per unit time. It can be given by :

I=\dfrac{q}{t}

Substitute all the values in the above formula

I=\dfrac{5000\ C}{3600\ s}\\\\=1.38\ A

So, the current intensity is 1.38 A.

8 0
2 years ago
Q1: A cyclist brakes to a stop. His thinking distance was 1m and his braking distance was 3m. What was his overall stopping dist
weeeeeb [17]

Answer:

1.) 4m

2.) 37 m

3.) 62m

4.) 2.5 s

Explanation:

1.) Given that the

Thinking distance = 1m

Breaking distance = 3m

Stopping distance = breaking distance + thinking distance

Stopping distance = 1 + 3 = 4m

2.) Given that the

Stopping distance = 52 m

Thinking distance = 15m

Breaking distance = 52 - 15 = 37m

3.) The stopping distance = 76m

Thinking distance = 14m

Breaking distance = 76 - 14 = 62m

It take the brakes 62m to slow the car down to a stop.

4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?

Thinking = stopping distance - braking distance

Thinking distance = 28 - 18 = 10m

Speed = distance/time

4 = 10/reaction time

Reaction time = 10/4

Reaction time = 2.5 s

5.) Question incomplete

5 0
3 years ago
When a the irregularities of one surface come into contact with those of another surface ,occurs
ser-zykov [4K]
The answer to the question is friction
6 0
3 years ago
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