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3 years ago

5

The scanning process and magnetic lenses used in a scanning electron microscope often results in fair to poor resolution and "fu

zzy" images.
(A)True
(B)False

1 answer:

algol133 years ago

3 0

Answer:

(B)False is the answer.

Explanation:

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After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

alexira [117]

Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

6 0

3 years ago

Describe how you would make or construct a wet cell. What basic part would you need? How would you use them to produce a voltage

polet [3.4K]

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4 0

3 years ago

During an oil spill, oil coats the surface of the water, endangering sea life. Why doesn’t oil dissolve in ocean water?

Natasha2012 [34]

The properties of oil and water do not mix

5 0

3 years ago

How much heat must be removed from 456 g of water at 25.0°C to change it into ice at - 10.0°C ? The specific heat of ice is 2090

cupoosta [38]

Answer:209.98 kJ

Explanation:

mass of water $m=456 gm$

Initial Temperature of Water $T_i=25^{\circ}C$

Final Temperature of water $T_f=-10^{\circ}C$

specific heat of ice $c=2090 J/kg-K$

Latent heat $L=33.5\times 10^4 J/kg$

specific heat of water $c_{water}=4.184 KJ/kg-K$

Heat require to convert water at $T=25^{\circ}C$ to $T=0^{\circ}C$

$Q_1=0.456\times 4.184\times (25-0)=47.69 kJ$

Heat require to convert water at $T=0^{\circ}$ to ice at $T=0^{\circ}$

$Q_2=m\times L=0.456\times 33.5\times 10^4=152.76 kJ$

heat require to convert ice at $T=0^{\circ} C\ to\ T=-10^{\circ} C$

$Q_3=0.456\times 2090\times (0-(-10))=9.53 kJ$

Total heat $Q=Q_1+Q_2+Q_3$

$Q=47.69+152.76+9.53=209.98 kJ$

7 0

3 years ago

A 75-hp (shaft output) motor that has an efficiency of 91% is worn out and is replaced by a high efficiency 75-hp motor that has

ZanzabumX [31]

Answer:

The heat gain of the room due to higher efficiency is 2.84 kW.

Explanation:

Given that,

Output power of shaft = 75 hp

Efficiency = 91%

High efficiency = 95.4%

We need to calculate the electric input given to motor

Using formula of efficiency

$\eta=\dfrac{Work\ Output}{Work\ input}$

$Work\ Input =\dfrac{Work\ output}{\eta}$

$Work\ Input =\dfrac{75\times746}{0.91}$

$Work\ Input =61483.51\ W$

$Work\ Input = 61.48 kW$

We need to calculate the electric input

For, heigh efficiency

$Work\ Input_{inc} =\dfrac{75\times746}{0.954}$

$Work\ Input_{int} =58647.7\ W$

$Work\ Input_{int} = 58.64\ kW$

The reduction of the heat gain of the room due to higher efficiency is

$Q=Work\ Input-Work\ Input_{int}$

Put the value into the formula

$Q=61.48 -58.64$

$Q=2.84\ kW$

Hence, The heat gain of the room due to higher efficiency is 2.84 kW.

3 0

3 years ago