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Rzqust [24]
2 years ago
6

When was the Hubble telescope launched​

Physics
2 answers:
SpyIntel [72]2 years ago
5 0

Answer:

April 24, 1990 is the answer

MrRissso [65]2 years ago
4 0
April 24 1990 is the correct answer
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A racing car accelerates at the end of the race from a speed of 100
nevsk [136]

4/3 m/s ( approximately 1.3333... m/s)

5 0
2 years ago
Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?
user100 [1]

Answer:

The answer is A.

Explanation:

5 0
2 years ago
A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

8 0
3 years ago
How can you predict a child'a height?
Svet_ta [14]
A child height can be very tall or short
3 0
3 years ago
The noise level coming from a pig pen with
sweet [91]

Answer:

The decibel of the remaining pigs is 51.5 dB.

Explanation:

Decibel (dB) is a unit of measure of the intensity of a given sound.

Number of pigs = 199, noise level = 74.3 dB.

Given that the intensity (I) of the sound from the pen is proportional to the number of pigs (N), thus:

                       I    \alpha  N

                       I = kN

where k is the constant of proportionality.

⇒                    k = \frac{I}{N}

                         = \frac{74.3}{199}

                      k = 0.3734

When 61 numbers of pigs were removed, the number of remaining pigs (N) squealing at their original level is 138.

Thus, the becibel level (I) of the remaining pigs can be determined by:

                  I = kN

                    = 0.3734 × 138

                   = 51.53 dB

The becibel level (I) of the remaining pigs is 51.53 dB.

6 0
3 years ago
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