Answer:
The answers are in the explanation.
Explanation:
The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:
Increasing temperature of ice from -10°C - 0°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g
Q = 2.06J/g°C*10°C*10g
Q = 206J
Change from solid to liquid:
The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:
Q = 333.55J/g*10g
Q = 3335.5J
Increasing temperature of liquid water from 0°C - 100°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g
Q = 4.18J/g°C*100°C*10g
Q = 4180J
Change from liquid to gas:
The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:
Q = 2260J/g*10g
Q = 22600J
Increasing temperature of gas water from 100°C - 120°C:
Q = S*ΔT*m
Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g
Q = 1.87J/g°C*20°C*10g
Q = 374J
Total Energy:
206J + 3335.5 J + 4180J + 22600J + 374J =
30695.5J =
30.7kJ
Enter a chemical formula to calculate its molar mass and elemental composition: Notice: your ... as a zero '0' Molar mass of Na2Co3*10H2O<span> is 402.9319 g/mol ...</span>
Li + H2O →<span> LiOH + H2
The equation is currently unbalanced, so to balance it out, you have to have the same number of each molecule on each side. It'll look like this:
</span>2Li + 2H2O → <span>2LiOH + H2
</span>
Also, in case you want to identify the phases as well, it'll be like this:
2Li (s) + 2H2O (l) → 2LiOH (aq) + H2 (g)
"s" is solid.
"l" is liquid.
"aq" is aquas.
"g" is gas.
I cannot answer your question about a image without being able to see it myself.
