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lys-0071 [83]
2 years ago
7

NEED HELP ASAP

Chemistry
2 answers:
ira [324]2 years ago
8 0

Answer:

i think its the 3 thired one sorry if rong but good luck

Explanation:

pychu [463]2 years ago
7 0

Answer:

The sample is made up of a single element. t or f

Explanation:

Forgot about the t or f!   Its true.

Dam bro.....

1. T

2. F

3. T

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There are two opposing processes that occur in a solution in contact with undissolved solute. These are dissolving and ________.
Alex777 [14]

Answer:

c. crystallization

Explanation:

The opposing process that occur in a solution in contact with undissolved solute are dissolution and crystallization.

In the dissolution process the solid substance coverts into liquid state and mixes with solution. Whereas in Crystallization the the chemical is converted from the liquid solution to solid crystal state.

3 0
3 years ago
What is the formula of the compound formed between the potassium ion and the sulfide ion?
KIM [24]
The formula for K+ and S-2 is K2S because you need 2 potassium ions to balance out the sulfide ion
4 0
3 years ago
When a scientist shares her findings with other scientists she is
finlep [7]

Answer:

communicating results

Explanation:

5 0
3 years ago
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How many grams of Co2 are produced from 12 g of CH4 and 133 g of O2
Andru [333]

Answer:

m_{CO_2}=33gCO_2

Explanation:

Hello,

In this case the undergoing chemical reaction is:

CH_4+2O_2\rightarrow CO_2+2H_2O

Next we identify the limiting reactant with the given amounts of methane and oxygen by computing the available moles of methane and the moles of methane consumed by the 133 g of oxygen:

n_{CH_4}^{available}=12g*\frac{1mol}{16g} =0.75molCH_4\\n_{CH_4}^{consumed\ by\ O_2}=133gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2}=2.08molCH_4

In such a way, the limiting reactant is methane with 0.75 moles which produce the following mass of carbon dioxide:

m_{CO_2}=0.75molCH_4*\frac{1molCO_2}{1molCH_4} *\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=33gCO_2

Best regards.

7 0
3 years ago
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7 0
3 years ago
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