Answer:
R = 28.125 ohms
Explanation:
Given that,
The voltage of a bulb, V = 4.5 V
Current, I = 0.16 A
We need to find the resistance of the filament. Using Ohm's law,
V = IR
Where
R is the resistance of the filament
So,
So, the resistance of the filament is equal to 28.125 ohms.
Answer:
528 liter.
Explanation:
Volume of the tank(cuboid) = l*b*h
But volume of the water = l*b*h
Where
l= length of the tank
b = width of the tank
h = the length from the bottom of the tank,
3.55 in to m,
0.09017m
Length of the water in the tank = 0.570 - 0.09017
= 0.47983 m.
Volume = 0.47983*0.710*1.55
= 0.528 m3.
1 m3 = 1000 liter.
0.528 m3 = 0.528*1000
= 528 liter
50 strands is the standard procedure
The answer is 165.3 cm³.
P1 * V1 / T1 = P2 * V2 / T2
The initial sample:
P1 = 84.6 kPa
V1 = 215 cm³
T1 = 23.5°C = 23.5 + 273 K = 296.5 K
At STP:
P2 = 101.3 kPa
V2 = ?
T2 = 273 K
Therefore:
84.6 * 215 / 296.5 = 101.3 * V2 / 273
61.34 = 101.3 * V2 / 273
V2 = 61.34 * 273 / 101.3
V2 = 165.3 cm³
