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sdas [7]
2 years ago
9

What minimum number of cycles are necessary for the engine to lift a rock of mass 570 kg through a height of 150 m?

Physics
1 answer:
gogolik [260]2 years ago
6 0
5 is the minimum number of cycles necessary for the engine to lift a rock of mass 570 kg
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The ms = 0.5645 and mk=0.1113 for a 30 N box on level ground. What level force is needed to start the box moving
nevsk [136]

Answer:

16.935 N

Explanation:

In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

F_f = \mu_s (mg)

where

\mu_s = 0.5645 is the coefficient of static friction

(mg) = 30 N is the weight of the box

Therefore, the condition for F must be:

F \geq F_f\\F \geq \mu_k (mg)=(0.5645)(30 N)=16.935 N

So, the applied force must be greater than this value.

3 0
3 years ago
The distance from Earth to the North Star is about 430 light-years. Which of the following statements describes why scientists u
vampirchik [111]

Answer:

D

Explanation:

D

7 0
3 years ago
Difference between effort and load​
scoray [572]

<u>Answer</u>:

Effort is the unaltered force. Load is the altered force.

4 0
3 years ago
2
luda_lava [24]

Answer:

500000N/m²

5250N

Explanation:

Given parameters:

Depth(H) = 50m

Density of water  = 1000kg/m³

Acceleration of free fall  = 10m/s

Unknown:

Pressure the water exerts on the diver = ?

Solution:

Pressure is the force per unit area on a body. In fluids, pressure is the product of density, gravity and height

  Pressure in fluids  = Density x acceleration due to gravity x height

Input the variables and solve;

    Pressure in fluids  = 1000 x 10 x 50  = 500000N/m²

B.

width of window = 150mm

height of window = 70mm

Force water exerts on the window = ?

To solve this problem;

         Pressure  = \frac{Force}{Area}

Area of the window = width x height  = 150 x 10⁻³ x 70 x 10⁻³

                                                           = 1.05 x 10 ⁻²m²

Force  = pressure x area

Input the variables;

             = 500000N/m²   x  1.05 x 10 ⁻²m²

             = 5250N

4 0
3 years ago
A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a d
Angelina_Jolie [31]

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?

If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.

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