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hammer [34]
3 years ago
7

*

Chemistry
1 answer:
tankabanditka [31]3 years ago
3 0
Watershed
A watershed is an entire river system of an area drained by a river and its tributaries
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neonofarm [45]
Mass number of calcium isotopes

mass numberi the number of proton + neutron

number of proton for calcium is 20 regardless of isotopes

hence the only difference between calcium isotopes are rhe number of neutron
6 0
3 years ago
Jordan is doing a science fair project on the effect of music on the growth of tomatoes. He has two tomatoe plants,plant A and p
krek1111 [17]
The control group is the type of tomato the plants are.
The independent variable is the type of music played.
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4 years ago
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3 years ago
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Electronic transitions (i.e., absorption of uv or visible light) of the conjugated molecule butadiene can be approximated using
dlinn [17]

Answer:

2.51 Angstroms

Explanation:

For a particle in a one dimensional box, the energy level, En, is given by the expression:

En = n²π² ħ² / 2ma²

where n is the energy level, ħ²  is Planck constant divided into 2π, m is the mass of the electron ( 9.1  x 10⁻³¹ Kg ), and a is the length of the one dimensional box.

We can calculate  the change in energy, ΔE, from n = 2 to n= 3  since we know the wavelength of the transition  ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the  length a.

λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m      ( SI units )

ΔE = 6.626 x 10⁻³⁴ J·s x  3 x 10⁸ m/s  / 2.07 x 10⁻⁷ m

ΔE   = 9.60 x 10⁻¹⁹ J

ΔE(2⇒3) = ( 3 - 2 )  x  π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

9.60 x 10⁻¹⁹ J  =  π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

⇒ a = 2.51 x 10⁻¹⁰ m

Converting to Angstroms:

a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms

6 0
4 years ago
Please help me i’m struggling
Marrrta [24]

Answeeeeer:

 A. cell

Explanation:

Since A is the smallest in the chart, that would correspond to the cell because thats the smallest out of Tissue, Organ and Organism.

3 0
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