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3 years ago

You get points!! IMPORTANT

Physics

2 answers:

aksik [14]3 years ago

6 0

Answer:

Explanation:

saveliy_v [14]3 years ago

4 0

Answer:True.

Explanation:

If charged with DUI Manslaughter it is 1. A DUI charge and then can be moved to vehicular manslaughter sooo thats more charges is how I see it.

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How long will bus take to travel 150 km at an average speed of 40km/hr

romanna [79]

Answer:

3.75 hours

Explanation:

By $v = \frac{d}{t}$

where v is the velocity (or speed in this case)

d is the distance travelled

t is the time taken

$t = \frac{150}{40}=3.75$
Therefore it takes 3.75 hours for the bus to travel 150 km and 40 km/hr.

7 0

2 years ago

A coating is being applied to reduce the reflectivity of a pane of glass to light with a wavelength of 522 nm incident near the

fredd [130]

Answer:

t = 94.91 nm

Explanation:

given,

wavelength of the light = 522 nm

refractive index of the material = 1.375

we know the equation

c = ν λ

where ν is the frequency of the wave

c is the speed of light

$\nu= \dfrac{c}{\nu\lambda}$

$\nu = \dfrac{3\times 10^8}{522 \times 10^{-9}}$

ν = 5.75 x 10¹⁴ Hz

the thickness of the coating will be calculated using

$t = \dfrac{\lambda}{4\mu_{material}}$

$t = \dfrac{522 \times 10^{-9}}{4\times 1.375}$

t = 94.91 nm

the thickness of the coating will be equal to t = 94.91 nm

7 0

3 years ago

A car starts from rest and travels 25 m in 5 seconds at constant velocity. It then reverses 5 m in 10 seconds at constant veloci

natali 33 [55]

Answer:

the car is going to same sped !

Explanation:

I just now luv

8 0

4 years ago

(I will give brainliest whoever helps me !!)

lorasvet [3.4K]

C. Forces have mass and take up space

3 0

3 years ago

Suppose that you observe light emitted from a distant star to be at a wavelength of 525 nm. The wavelength of light to an observ

Tomtit [17]

Answer:

The velocity of the star is 0.532 c.

Explanation:

Given that,

Wavelength of observer = 525 nm

Wave length of source = 950 nm

We need to calculate the velocity

If the direction is from observer to star.

From Doppler effect

$\lambda_{0}=\sqrt{\dfrac{c+v}{c-v}}\times\lambda_{s}$

Put the value into the formula

$525=\sqrt{\dfrac{c+v}{c-v}}\times950$

$\dfrac{c+v}{c-v}=(\dfrac{525}{950})^2$

$\dfrac{c+v}{c-v}=0.305$

$c+v=0.305\times(c-v)$

$v(1+0.305)=c(0.305-1)$

$v=\dfrac{0.305-1}{1+0.305}c$

$v=−0.532c$

Negative sign shows the star is moving toward the observer.

Hence, The velocity of the star is 0.532 c.

7 0

3 years ago