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Ivahew [28]
3 years ago
5

Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?

Physics
1 answer:
kolbaska11 [484]3 years ago
8 0

Average speed is defined as the ratio of total distance covered in total given time

speed = \frac{distance}{time}

here we know that total distance that man moved is

d_1 = 200 km

d_2 = 100 km

so total distance is

d = d_1 + d_2

d = 200 km + 100 km

d = 300 km

now here total time of the motion is

t_1 = 6 hours

t_2 = 4 hours

total time will be given as

t = t_1 + t_2

t = 6 + 4 = 10 hours

now by above formula

v_{avg} = \frac{300}{10}

v_{avg} = 30 km/h

so his average speed is 30 km/h

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Suppose that the sound level of a conversation is initially at an angry 71 dB and then drops to a soothing 54 dB. Assuming that
Goryan [66]

Answer:

Explanation:

In the decibel scale , intensity of sound changes logarithmically as follows

10log\frac{I}{I_0} = Value in decibel scale , the value of I₀ = 10⁻¹² W /m².

Putting the values

10log\frac{I}{10^{-12}} = 71

log\frac{I}{10^{-12}} = 7.1

\frac{I}{10^{-12}} = 10^{7.1}

I= 10^{-4.9} W/m²

Similarly for 54 dB sound intensity can be given as follows

I = 10⁻¹² x 10^{5.4}

I= 10^{-6.6 } W / m²

For intensity of sound the relation is as follows

I = 2π²υ²A²ρc where υ is frequency , A is amplitude , ρ is density of air and c is velocity of sound .

Putting the given values for 71 dB

I= 10^{-4.9}  = 2π² x 504²xA²x 1.21 x  346

A² = 60.03 x 10⁻¹⁶

A = 7.74 x 10⁻⁸ m

For 54 dB sound

10^{-6.6} = 2π² x 504²xA²x 1.21 x  346

A² = 1.1978 x 10⁻¹⁶

A = 1.1 x 10⁻⁸ m

6 0
3 years ago
What is work please give ans​
Fed [463]
Work= force x displacement :)
8 0
2 years ago
A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c
Anna35 [415]

The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

4 0
2 years ago
Water flows from the bottom of a storage tank at a rate of r(t) = 300 − 6t liters per minute, where 0 ≤ t ≤ 50. Find the amount
SSSSS [86.1K]

r(t) models the water flow rate, so the total amount of water that has flowed out of the tank can be calculated by integrating r(t) with respect to time t on the interval t = [0, 35]min

∫r(t)dt, t = [0, 35]

= ∫(300-6t)dt, t = [0, 35]

= 300t-3t², t = [0, 35]

= 300(35) - 3(35)² - 300(0) + 3(0)²

= 6825 liters

7 0
3 years ago
When is a model used in science?
Mamont248 [21]
C. Both of the above
8 0
3 years ago
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