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MA_775_DIABLO [31]
3 years ago
9

To estimate the benefits of an SAT prep course, a random sample of 10 students enrolled in the course is selected. For each of t

hese students, their entrance score on the exam taken at the beginning of the course is recorded. Their exit score on the exam they take at the end of the course is recorded as well. The table displays the scores.
A 3-column table with 10 rows. Column 1 is labeled student with entries 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Column 2 is labeled Before with entries 800, 870, 860, 820, 1140, 1050, 850, 910, 830, 1140. Column 3 is labeled after with entries 1100, 1010, 1000, 980, 1410, 1270, 1020, 1010, 1060, 1340.

A 98% confidence interval for the mean difference (after – before) in score is 137.04 points to 248.96 points. Based on the confidence interval, is it reasonable to claim that the SAT prep course is beneficial?

No, 0 is not contained in the confidence interval.
Yes, 0 is not contained in the confidence interval.
No, the confidence interval only contains positive values.
Yes, the confidence interval only contains positive values.
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

,, yes the confidence interval only contains positive values

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3 years ago
Describe the transformations of the following function. y=tan(2x-π)
Romashka [77]

Answer:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

y = tan(2x - π)

y = tan (2*(x-π/2))

We can compare it to its parent function

g(x) = tan(x)

The answer is

Option a.

Horizontal shrink by 1/2 and horizontal shift of π/2 to the right

7 0
4 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
Find the answers to this activity
diamong [38]

Answer:

(224)10 = (E0)16

I dont know why it wouldnt be right this is the answer...Im acually confused now

Step-by-step explanation:

(224)10 = (E0)16

Step by step solution

Step 1: Divide (224)10 successively by 16 until the quotient is 0:

224/16 = 14, remainder is 0

14/16 = 0, remainder is 14

Step 2: Read from the bottom (MSB) to top (LSB) as E0. This is the hexadecimal equivalent of decimal number 224

5 0
3 years ago
Identify the constant of proportionality for each direct variation below.
andriy [413]

Answer:

see explanation

Step-by-step explanation:

The equation of 2 quantities in direct proportion is

y = kx ← k is the constant of proportionality

1

y = - 4x ← in standard form

with k = - 4

2

\frac{y}{x} = 2 ( multiply both sides by x )

y = 2x ← in standard form

with k = 2

3

\frac{x}{y} = 3 ( multiply both sides by y )

x = 3y ( divide both sides by 3 )

\frac{1}{3} x = y ← in standard form

with k = \frac{1}{3}

3 0
3 years ago
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