The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
To find the answer, we have to know about the focal length of correcting lens.
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How to find the focal length of
correcting lens?</h3>
- If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,
- It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,
Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
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Answer:
4.39 x 10^-19 J
Explanation:
q1 = 1.6 x 10^-19 C
q2 = - 1.6 x 10^-19 C
r1 = 3 x 10^-10 m
r2 = 7 x 10^-10 m
The formula for the potential energy is given by
U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)
U1 = - 7.68 x 10^-19 J
U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)
U2 = - 3.29 x 10^-19 J
Change in potential energy is
U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J
Explanation:
In geology, there are 5 divisions of time on the time scale. They are:
- eons
- eras
- periods
- epochs
- ages
Eons are the largest time period, while ages are the shortest time period. The rest of the above listed are in between the two.
Well I don't know !
Let's work it out:
Weight = (mass) x (local acceleration of gravity)
117.6 N = (12 kg) x (gravity)
Gravity on Planet A = (117.6 N) / (12 kg)
= 9.8 m/s² exactly
The gravity on Planet-A is so close to Earth gravity
that nobody could ever tell the difference without
making sensitive measurements.
They are essentially equal.
it’s B (because 20 Is smaller than 50)
