Answer: 1.02 x 10^-2 N/C to the east
Explanation:
Hi,
To find the magnitude of the electric field in this problem, you simply have to use the formula F = qE
F = Force
q = charge of the particle
E = magnitude of the electric field
Here, we are told that a force is being acted on an electron and we aren't told any specific quantity of charge for the electron. Therefore, we can assume that the charge of the electron will be its conventional charge of 1.602 x 10^-19 C
We are also given the force which is 1.64 x 10^-21 N
We solve for E
E = F/q
We plug in
E = (1.64 x 10^-21 N)/(1.602 x 10^-19 C)
E = 1.02 x 10^-2 N/C
The direction will be the east because the angle didn't change.
