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Gnoma [55]
3 years ago
8

The number of revolutions of two pulleys is inversely proportional to their diameters. If a 24-inch diameter pulley making 400 r

evolutions per minute is belted to an 8-inch diameter pulley, find the number of revolutions per minute of the smaller pulley.
133 1/3
800
1,200 ...?
Physics
2 answers:
bixtya [17]3 years ago
8 0
The correct answer is 1200.
nalin [4]3 years ago
3 0
<h3><u>Answer;</u></h3>

1200

<h3><u>Explanation;</u></h3>
  • Since diameter (d) is inversely proportional to the revolutions (n) are

<em>Then; dn=k  </em>

We can use the relationship to find the unknown, k:  

<em>k = dn  </em>

<em>k = (24)(400) = 9600  </em>

Then use k to find the unknown n:  

<em> k= dn  </em>

<em>9600 = 8n  </em>

<em>n = 1200  </em>

<u> = 200 rpm</u>

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The heat capacity of 0.125Kg of water is measured to be 523j/k at a room temperature.Hence, calculate the heat capacity of water
Naily [24]

Answer:

A. 4148 J/K/Kg

B. 4148 J/K/L

Explanation:

A. Heat capacity per unit mass is known as the specific heat capacity, c.

C = Heat capacity/mass(kg)

C = (523 J/K) / 0.125 Kg = 4148 J/K/Kg

B. Volume of water = mass/density

Density of water = 1 Kg/L

Volume of water = 0.125 Kg/ 1Kg/L

Volume of water = 0.125 L

Heat capacity per unit volume = (523 J/K) / 0.125 L

Heat capacity per unit volume = 4148 J/K/L

5 0
3 years ago
What type of energy<br> transformation happens in<br> hydro-electric power?
s344n2d4d5 [400]

Answer:

wind power

Explanation:

4 0
3 years ago
A car is designed to get its energy from a rotating flywheel with a radius of 1.50 m and a mass of 430 kg. Before a trip, the fl
fiasKO [112]

Answer:

a

  KE  =  7.17 *10^{7} \ J

b

 t = 6411.09 \ s

Explanation:

From the question we are told that

    The radius of the flywheel is  r =  1.50 \ m

      The mass of the flywheel is m  = 430 \ kg

          The rotational speed of the flywheel is w  =  5,200 \ rev/min = 5200 *  \frac{2 \pi }{60} =544.61 \ rad/sec

      The power supplied by the motor is  P  =  15.0 hp =  15 * 746 =  11190 \ W

         

     Generally the moment of inertia of the flywheel is  mathematically represented as

       I  = \frac{1}{2} mr^2

substituting values

       I  = \frac{1}{2}  ( 430)(1.50)^2

       I  = 483.75 \  kgm^2

The kinetic energy that is been stored is  

       KE  =  \frac{1}{2} * I * w^2

substituting values

        KE  =  \frac{1}{2} * 483.75 * (544.61)^2

        KE  =  7.17 *10^{7} \ J

Generally power is mathematically represented as

          P =  \frac{KE}{t}

=>      t =  \frac{KE}{P}

substituting the value

        t = \frac{7.17 *10^{7}}{11190}

        t = 6411.09 \ s

3 0
3 years ago
What is the force of a 1500 kg car accelerating at 45 m/s2 ?
tiny-mole [99]

Answer:

67500

Explanation:

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3 0
3 years ago
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mart [117]

Answer:

3) 52500N

Explanation:

We use the mathematical definition of impulse as follows;

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were F is the force experienced, t is the time of impact, m is the mass of the object and v is the velocity of impact.

Given; m = 4.5kg, v = 35m/s, t = 3 milliseconds

however, 3milliseconds=3*10^{-3}s

From equation (1);

F=\frac{mv}{t}.............(2).

Substituting all necessary values into equation (2), we obtain the following;

F=\frac{4.5*35}{3*10^{-3}}}\\\\F= \frac{157.5.5}{0.003}\\\\F=52500N

6 0
3 years ago
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