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Elan Coil [88]
3 years ago
10

The intensity of sunlight falling on the earth is about 1.4 kw/m2 (before any gets absorbed by our atmosphere). at what rate doe

s the sun emit light energy? (the earth-sun distance = 1.5 × 108 km and the earth's radius = 6.4 × 103 km.)
Physics
1 answer:
xxTIMURxx [149]3 years ago
6 0
The area of the Earth (Ae) that is irradiated by is given by:

Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2

On the Earth, insolation (We) = Psun/Ae

Therefore,
Psun (Rate at which sun emits energy) = We*Ae = 1.4*2.827*10^23 = 3.958*10^23 kW = 3.958*10^26 W
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Explanation:

a)

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In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.

Then, additional torques are applied, so that the net torque suddenly equal to zero, so:

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So cases (a) and (b) are basically the same situation, as the net torque is zero in both cases, so the object acts in the same way.

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