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3 years ago

How many moles of CO2 are there in 2.55 x 10 18 molecules of CO2?

Chemistry

1 answer:

cluponka [151]3 years ago

6 0

Answer: There are $4.23\times 10^{-6}moles$ of $CO_2$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

$\text{Number of moles}=\frac{2.55\times 10^{18}}{6.023\times 10^{23}}=0.423\times 10^{-5}moles$

Thus there are $4.23\times 10^{-6}moles$ of $CO_2$

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What is the structural formula of pent-3-en-1-yl? <br>Thx

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3 years ago

If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em

erica [24]

Answer: Wavelength associated with the fifth line is 397 nm

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $10973731.6m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2$

$\frac{1}{\lambda}=2.52\times 10^{6}m$

$\lambda}=3.97\times 10^{-7}m=397 nm$ $1nm=10^{-9}m$

Thus wavelength λ associated with the fifth line is 397 nm

7 0

4 years ago

Based on the information provided here, crude oil is:

Anna007 [38]

THE EXPLINATION ANSWER: I think crude oil is a mixture because it is made up of compounds that can be separated using distillation, a physical process.

8 0

4 years ago

Use the ruler to determine the length of the line measured to the correct degree of precision. 13.2 cm 13.25 cm 130 cm 132 mm

lapo4ka [179]

Your answer would be 13.25cm

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4 years ago

Read 2 more answers

solution of a weak acid HA has initial concentration c and acid ionization constant Ka. To what concentration should the acid be

soldier1979 [14.2K]

Answer:

The concentration c is equal to Ka

Explanation:

The acid will ionize as observed in the following reaction:

HA = H+ + A-

H+ is the proton of the acid and A- is the conjugate base . The equation to calculate the Ka is as follows:

Ka = ([H+]*[A -])/[HA]

Initially we have to:

[H+] = 0

[A-] = 0

[HA] = c

During the change we have:

[H+] = +x

[A-] = +x

[HA] = -x

During balance we have:

[H+] = 0 + x

[A-] = 0 + x

[HA] = c - x

Substituting the Ka equation we have:

Ka = ([H+]*[A-])/[HA]

Ka = (x * x)/(c-x)

x^2 + Kax - (c * Ka) = 0

We must find c, having as [H+] = 1/2c. Replacing we have:

(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0

(c^2)/2 + Ka(c / 2 - c) = 0

(c^2)/2 + (-Ka * c/2) = 0

c^2 -(c*Ka) = 0

c-Ka = 0

Ka = c

8 0

3 years ago