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3 years ago

In the calculations it was assumed that:

Chemistry

1 answer:

Rus_ich [418]3 years ago

8 0

Answer:

Following are the responses to the given points:

Explanation:

Form the above-given question, it indicates that the bromate ion green ionizes in water to form a green-blue solution, therefore the before adding the HCL it indicator was in anionic from hence it is written as In^{-} therefore the HCL is mixed which the anion is protonated to give HIN

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An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula

uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

0.545 gr Al

0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al

0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

0.02 mol Al / 0.02 = 1 Al

0.03 mol O / 0.02 = 1.5 O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

1Al * 2 = 2Al

1.5O * 2 = 3O

Now the answer is given correctly:

Al2O3

8 0

3 years ago

Calculate how much carbohydrate a 175-pound athlete who is in training 4-5 hours per day should eat each day in order to enhance

Kamila [148]

Answer:

The athlete should consume about 476 g of carbohydrates per day to maintain a good storage of glycogen in his body

Explanation:

For an athlete who trains daily, 5 to 7 g of carbohydrates per Kg of body weight per day is recommended;

∴ m athlete = (175 Lb)×(0.453592 Kg/Lb) = 79.3787 Kg

⇒ m carbohydrate = (79.3787 Kg)×( 6 g carbohydrate/ Kg.day) = 476.27 g carbohydrate/day

5 0

3 years ago

How do you balance an equation O2 to O3 reaction

Minchanka [31]

3O2 ------> 2O3

6O 6O

6 atoms of O before and after reaction.

4 0

3 years ago

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce

Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{3.49}{3.50}=0.997g$

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{9.00}{6.00}=1.5g$

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0

4 years ago

What type of macromolecule carries out catalysis in biological systems?

IgorC [24]

Carbohydrates called starches

3 0

4 years ago