Answer:
The bird's speed immediately after swallowing is 6.17 m/s.
Explanation:
Given that,
Mass of the bird, m = 270 g = 0.27 kg
Initial speed of the bird, u = 5 m/s
Mass of the insect, m' = 11 g = 0.011 kg
Initial speed of the insect, u' = 35 m/s
We need to find the bird's speed immediately after swallowing. Let it is given by V. Using the conservation of momentum as :
So, the bird's speed immediately after swallowing is 6.17 m/s.
<span>they are related because since you push something you are using force and the force the of the distance is how they are related</span>
Answer:
7,546 J
Explanation:
recall that Potential energy is given by
P.E = mgΔh
where m = 70kg (given)
g = 9.8 m/s² (acceleration due to gravity)
Δh = change in height
= distance from top of building to top of car
= height of building - height of car
= (5+8) - 2
= 11m
substituting all these into the equation:
P.E = mgΔh
= 70 x 9.8 x 11
= 7,546 J
C. The pressure decreases, and we can precisely predict by how much.
