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kari74 [83]
3 years ago
7

Which of these devices does NOT contain a magnet or electromagnet?

Physics
2 answers:
Black_prince [1.1K]3 years ago
7 0
I think it is D a light bulb
andrey2020 [161]3 years ago
3 0
The answer is D.
A lightbulb has no magnet or electromagnet.
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when an object moves with constant velocity, does its average velocity during any time interval differ from its instataneous vel
BigorU [14]
For a constant-velocity object, the average and instantaneous are the same.  So the answer is no.  It's like taking a running average of a string of numbers that are all the same number.  The average is always the sum of the numbers divided by how many have accumulated, which will always equate to the repeated number.
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A huge rotating cloud of particles in space gravitate together to form an increasingly dense ball. As ir shrinks in size, the cl
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Answer:

rotates faster

Explanation:

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5 0
3 years ago
45 grams in kilo grams
Hunter-Best [27]

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7 0
3 years ago
Read 2 more answers
An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f
soldi70 [24.7K]

Answer:

D.

Explanation:

To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.

The magnetic field is given by the equation:

B = \frac{\mu_0 I}{2\pi d}

Where,

\mu = Permeability constant

d = diameter

I = Current

For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:

B_1 = \frac{\mu_0 I}{2\pi d}

B_2 = \frac{\mu_0 I}{2\pi 2d}

The ratio of change between the two is given by:

\frac{B_2}{B_1} = \frac{\frac{\mu_0 I}{2\pi d}}{\frac{\mu_0 I}{2\pi 2d}}

\frac{B_2}{B_1} = \frac{d}{2d}

\frac{B_2}{B_1} = \frac{1}{2}

B_2 = B_1 \frac{1}{2}

Therefore the correct answer is D.

4 0
2 years ago
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