calculate the temperature at which the reading on Fahrenheit scale is equal to half the reading of Celsius scale
1 answer:
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<u>Answer:</u>
Mass of C in 3.40 g of HCN =1.51 gram.
<u>Explanation:</u>
Mass of sample of HCN = 7.99 g
Mass of H in 7.99 g of HCN = 0.296 g
Mass of N in 7.99 g of HCN = 4.14 g
Mass of C in 7.99 g of HCN = (7.99-0.296-4.14) = 3.554 g
Now mass of HCN = 3.40 g
Mass of C in 3.40 g of HCN =
So mass of C in 3.40 g of HCN =1.51 gram.
Answer:
<em>radius of the loop = 7.9 mm</em>
<em>number of turns N ≅ 399 turns</em>
Explanation:
length of wire L= 2 m
field strength B = 3 mT = 0.003 T
current I = 12 A
recall that field strength B = μnI
where n is the turn per unit length
vacuum permeability μ = = 1.256 x 10^-6 T-m/A
imputing values, we have
0.003 = 1.256 x 10^−6 x n x 12
0.003 = 1.507 x 10^-5 x n
n = 199.07 turns per unit length
for a length of 2 m,
number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>
since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.
this length is also equal to the circumference of each loop
the circumference of each loop =
0.005 = 2 x 3.142 x r
r = 0.005/6.284 = = 0.0079 m =<em> 7.9 mm</em>