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aliina [53]
3 years ago
15

A large cooler is filled with water, as shown below. A large yellow cooler with a white valve at its bottom. How does the valve

on the cooler compare with the switch in an electric circuit? Opening the valve allows water to flow, just like opening a switch allows charges to flow. Opening the valve stops the flow of water, but closing a switch stops the flow of charges. Closing the valve stops the flow of water, but opening a switch stops the flow of charges. Closing the valve allows water to flow, just like closing a switch allows charges to flow.
Physics
2 answers:
gladu [14]3 years ago
6 0

Answer:

c. Closing the valve stops the flow of water, but opening a switch stops the flow of charges.

Explanation:

I just took the test on edge. Hope this helps and sorry if I'm late :)

vovangra [49]3 years ago
6 0

Answer:

C) Closing the valve stops the flow of water, but opening a switch stops the flow of charges.

Explanation:

I took the quiz and got it rightt goodluckk <3

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Answer:

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Explanation:

a) According to the diagram 1 in the attached image:

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Also:

v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j

If we comparing both sides of the expression:

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v_{C}=9.829*0.435=4.28in/s

b) According to the diagram 2 in the attached image:

r_{C/A}=12cos50i-12sin50j=7.713i-9.192j\\r_{B/C}=-3.856i+4.596j

v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j

Comparing both sides of the expression:

7.713w_{AC}-3=0\\w_{AC}=0.388rad/s\\v_{C}=3.575i

v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right]  \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2}  } =2.33in/s

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