A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.
<h3>How do we calculate volume?</h3>
Volume for the given equation will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ = molarity of KNO₃ = 2M
V₁ = volume of KNO₃ = 1mL
M₂ = molarity of final solution = 0.0080M
V₂ = volume of final solution = ?
On putting these values on the above equation, we get
V₂ = (2)(1) / (0.0080) = 250mL
Hence option (2) is correct.
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In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .
<u>Salient Features</u> :-
- The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
- The reducing ability of metals grows weaker while traversing down the series.
- The electro-positivity of metals also reduces while moving down the reactivity series.
- Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.
<u>The metal reactivity series is given below</u> :-
To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.
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Answer:
The first two options are correct
Explanation:
The first two options are part of the benefits of a parallel connection of bulbs in a circuit. Here, the voltage of each connecting bulb is the same as the voltage of the bulb in the circuit hence all the bulbs have the same voltage running through them. Thus, when one bulb is removed/burns out, it does not affect the remaining bulbs (those ones will remain lit). Also, the addition of bulb(s) does not cause the remaining bulbs in the circuit to get dimmer (since they will all have the same voltage).
The half-life of any substance is the amount of time taken for half of the original quantity of the substance present to decay. The half-life of a radioactive substance is characteristic to itself, and it may be millions of years long or it may be just a few seconds.
In order to determine the half-life of a substance, we simply use:
t(1/2) = ln(2) / λ
Where λ is the decay constant for that specific isotope.
Answer:
(2) Organelles must work together and their
activities must be coordinated
Explanation:
Organelles are usually located in cells. They are saddled with the role of performing specific functions in the cells for the overall functioning of life. In eukaryotic cells, the organelles are membrane bounded but in prokaryotic or primitive cells such is not the case.
Examples of cell organelles are ribosome, food vacuole, nucleus e.t.c. Just like organs in the body, organelles must work together in order to enhance life.