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Citrus2011 [14]
3 years ago
5

What protects living things from too much ultraviolets radiation?

Chemistry
1 answer:
mixas84 [53]3 years ago
8 0
The ozone layer of the Earth's atmosphere is what protects living things from too much ultraviolet radiation, if that's what you're asking about. 
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Help please for chemistry class
IRISSAK [1]

Answer:

option c is correct

Explanation:

the addition of catalyst does not effect the position or equilibrium constant and increase the forward and backward reaction in equal rates so no effect would be observed

3 0
3 years ago
An ionic bond involves the.....
Svetllana [295]
Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, or between two atoms with sharply different electronegativities, and is the primary interaction occurring in ionic compounds
5 0
3 years ago
Read 2 more answers
How can you increase the momentum of an object?
Nataliya [291]

Answer:

(c) by increasing it's mass

4 0
2 years ago
Read 2 more answers
33 protons 36 electrons 45 neutrons
Artist 52 [7]

As has an atomic number of 33, so it has 33 protons.  

It has a charge of 3-, so there are three more electrons than protons. Thus, there are 36 electrons.  

It has a mass of 75, which is the sum of neutrons and protons.  

33+n=75 ---> n = 75 - 33 = 42 neutrons  

The answer is e) 33 protons, 42 neutrons and 36 electrons.

6 0
3 years ago
For this question, the "entropy term" refers to "-TΔS". Addition reactions are generally favorable at low temperatures because _
nata0808 [166]

Answer:

Lowering the temperature typically reduces the significance of the decrease in entropy. That makes the Gibbs Free energy of the reaction more negative. As a result, the reaction becomes more favorable overall.  

Explanation:

In an addition reaction there's a decrease in the number of particles. Consider the hydrogenation of ethene as an example.

\rm H_2C\text{=}CH_2\; (g) + H_2\; (g) \stackrel{\text{Ni}^\ast}{\to} H_3C\text{-}CH_3\; (g).

When \rm H_2 is added to \rm H_2C\text{=}CH_2 (ethene) under heat and with the presence of a catalyst, \rm H_3C\text{-}CH3 (ethane) would be produced.

Note that on the left-hand side of the equation, there are two gaseous molecules. However, on the right-hand side there's only one gaseous molecule. That's a significant decrease in entropy. In other words, \Delta S < 0.

The equation for the change in Gibbs Free Energy for a particular reaction is:

\Delta G = \Delta H + (\underbrace{- T \, \Delta S}_{\text{entropy}\atop \text{term}}).

For a particular reaction, the more negative \Delta G is, the more spontaneous ("favorable") the reaction would be.

Since typically \Delta S < 0 for addition reactions, the "entropy term" of it would be positive. That's not very helpful if the reaction needs to be favorable.

T (absolute temperature) is always nonnegative. However, lowering the temperature could help bring the value of

8 0
3 years ago
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