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blondinia [14]
3 years ago
10

Faunal succession and fossil correlation relate to the principle of superposition because there are fossils of certain organisms

in a rock layer. By knowing the order in which the organisms came and that fossils of the same age mean the rock layers are the same age, scientists can determine the age of the rock layers with the youngest layers on top. True or False
Chemistry
2 answers:
yaroslaw [1]3 years ago
6 0

Answer:

Alright love the answer would be true

Gennadij [26K]3 years ago
5 0

Answer: it sounds true

Explanation:

You might be interested in
The isotope of carbon used in archaeological dating is 14^6C . How many protons, neutrons, and electrons does an atom of 14^6C h
vampirchik [111]

Answer:

6

8

6

Explanation:

 Isotope given:

                       ¹⁴₆C

In specie written as this;  

   Superscript  = Mass number

   Subscript  = Atomic number

To find the protons, it is the same as the atomic number;

                Protons  = Atomic number  = 6

Neutrons have no charges;

 Neutrons  = Mass number - Atomic number  =

  Neutrons  = 14 - 6  = 8

The number of electrons is the same as the atomic number = 6

8 0
3 years ago
A rectangular solid has a length of 3 cm a height of 4 cm and a width of 5 cm what is the solid volume ?
andrew11 [14]
Volume is 60 and the area is 94 have a great day
3 0
3 years ago
How many mole of oxygen are present in 3 mole of sodium sulfate, Na2SO4
GarryVolchara [31]
N(Na₂SO₄)=3 mol

n(O)=4n(Na₂SO₄)

n(O)=4*3=12 mol
3 0
3 years ago
Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH₄), by the following process:
kykrilka [37]

Answer:

6.75 g of HCN can be produced by the reaction

Explanation:

Complete reaction is:

2NH₃ (g) + 3O₂ (g) + 2CH₄ (g) → 2HCN (g) + 6H₂O (g)

Let's determine the moles of each reactant:

11.5 g . 1mol / 17g = 0.676 moles of ammonia

12 g . 1 mol / 32g = 0.375 moles of oxygen

10.5 g . 1mol/ 16 g =  0.656 moles of methane

Now is all about rules of three:

2 moles of ammonia reacts with 3 moles of O₂ and 2 moles of methane

0.676 moles of NH₃ may react with:

(0.676 . 3) /2 = 1.014 moles of O₂

(0.676 . 2) / 2 = 0.676 moles of methane

Both can be the limiting reactant.

3 moles of O₂ react with 2 moles of NH₃ and 2 moles of methane

0.375 moles of O₂ will react with:

(0.375 .2) / 3  = 0.375 moles

The same amount for methane, 0.375 moles

2 moles of CH₄ reacts with 3 moles of O₂ and 2 moles of NH₃

0.656 moles of methane would react with 0.656 moles of NH₃

(0.656 . 3 ) /2 = 0.437 moles of O₂   I do not have enough O₂

Oxygen is the limiting reactant → We can work with the reaction now.

Ratio is 3:2. 3 moles of oxygen produce 2 moles of cyanide

0.375 moles of O₂ may produce (0.375 .2 ) / 3 = 0.250 moles

If we convert the moles to mass → 0.250 mol . 27 g / 1mol = 6.75 g

4 0
3 years ago
12. help idk what to do at this point , I have notes and study till 3am , I still need help
GaryK [48]
I’m not good at this but I’m guessing it’ll be the first one!
5 0
3 years ago
Read 2 more answers
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