The smallest volume from among the following is

A person's heartbeat is 66 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th

BartSMP [9]

88(60) 24(365) that should be the answer after you figure it out.

5 0

3 years ago

Consider the cell notation Cd(s) | Cd(NO3)2(aq) || AgNO3(aq) | Ag(s) with standard reduction potentials for Cd2+ and Ag+ as -0.4

MakcuM [25]

The value of the Gibbs free energy shows us that the reaction is spontaneous.

<h3>What is the Gibbs free energy?</h3>

The Gibbs free energy is a quantity that helps us to be able to determine the spontaneity of a reaction.

In order to obtain the Gibbs free energy, we must obtain the Ecell as follows; 0.799V - (-0.402V) = 1.201 V

Now;

△G = -nFEcell

△G = -(2 * 96500 * 1.201)

△G = -232kJ/mol

Learn more about free energy:brainly.com/question/15319033?

#SPJ1

8 0

1 year ago

Le Châtelier's principle states that if a stress is applied to a system at equilibrium, the system will shift to relieve that st

zhuklara [117]

Answer:

1) Add more sulfate ions.

2) 1 M K₂SO₄.

Explanation:

1) Which of the following actions would shift this reaction toward solid barium sulfate?

Le Châtelier's principle states that if a stress is applied to a system at equilibrium, the system will shift to relieve that stress and attain the equilibrium again.

Add more sulfate ions will increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.

So, the right choice is: Add more sulfate ions.

2) In which of the following would barium sulfate be least soluble?

The answer is 1 M K₂SO₄, it has a common ion effect of SO₄⁻ ions that increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.

So, the solubility will decrease.

3 0

3 years ago

I attached my homework sheet, and can't figure it out. If anyone could help it would be great.

Lynna [10]

Answer:

I can't see the picture can you just text it to me so I can help you

7 0

3 years ago

Calculate the ph of the resulting solution if 34.0 ml of 0.340 m hcl(aq is added to

anyanavicka [17]

According to the reaction equation:

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

a) Part 1):

first, we need to get moles HCl = molarity * volume

= 0.34m * 0.034

= 0.01156 mol

then, we need moles of NaOH = molarity * volume

= 0.34 * 0.039

= 0.01326 mol

when NaOH excess:

∴ NaOH remaining = 0.01326 - 0.01156

= 0.0017 mol

when the total volume = 0.039 + 0.034

= 0.073 L

∴[OH] = moles / total volume

= 0.0017mol / 0.073 L

= 0.0233 M

∴ POH = -㏒[OH-]

= -㏒0.0233

= 1.63

∴ PH = 14- 1.63

= 12.37

b) part 2:

as we got moles HCl = molarity * volume

= 0.34 * 0.034

= 0.01156 mol

then moles NaOH = molarity * volume

= 0.39 * 0.044

= 0.01716 mol

NaOH remaining = 0.01716 - 0.01156

= 0.0056 mol

when the total volume = 0.034 + 0.044

= 0.078 L
∴[OH-] = 0.0056 / 0.078

= 0.0718 M

∴ POH = -㏒[OH-]

= -㏒0.0718

= 1.14

∴PH = 14 - POH

= 14 -POH

= 14 - 1.14

= 12.86

8 0

3 years ago

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