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neonofarm [45]
3 years ago
9

.

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:lmk when u have the answer

Explanation:

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If the temperature of water increases as you heat it, the temperature is the independent variable.
Simora [160]
False

becuase the temperates is dependant on heat or cold sources
5 0
3 years ago
Read 2 more answers
3. What causes the plates to be pulled apart?<br> PLEASE HELP
Tamiku [17]

Answer:

Hot magma rises from the mantle at mid-ocean ridges pushing the plates apart. Earthquakes occur along the fractures that appear as the plates move apart.:

6 0
3 years ago
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1.) Calculation: If 9.02 x 1024 particles of vinegar (HC2H3O2)HC2H3O2) are added to 16.5 moles of eggshell (CaCO3) and 6.35 mole
blsea [12.9K]

The theoretical yield of acetate is 2607 g. The actual yield of acetate is 1066.8 g. The percentage yield of acetate is 41%.

If 1 mole of vinegar contains 6.02  x 10^23 particles

x moles of vinegar contains 9.02 x 10^24 particles

x = 1 mole x 9.02 x 10^24 /6.02 x 10^23

x = 15 moles of vinegar

The reaction is as follows;

2HC2H3O2 + CaCO3 -----> Ca(C2H3O2)2 + H2O + CO2

Since 2 moles of vinegar reacts with 1 mole of carbonate

x moles of vinegar reacts with 16.5 moles of carbonate

x =  2 moles x 16.5 moles/ 1 mole

x = 33 moles of vinegar

We can see that the vinegar is the reactant in excess hence the carbonate is the limiting reactant.

Theoretical yield = 16.5 moles x 158 g/mol = 2607 g

Actual yield = 6.35 moles  x 158 g/mol = 1066.8 g

Percent yield = 1066.8 g/2607 g × 100/1

= 41%

Learn more: brainly.com/question/13440572?

7 0
3 years ago
The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a
crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = 1.52x10^{19} J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

k = koxe^{-Ea/RT}

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}

\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x10^{-4}

-1.67x10^{-5}xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

k1 = koxe^{-Ea/RT1}

2.46 = koxe^{-177x10^3/8.314x492}

1.61x10^{-19}ko = 2.46

ko = 1.52x10^{19} J/mol

3 0
3 years ago
27. The compound having only primary hydrogen atoms is ( ).
11111nata11111 [884]

Answer:

The correct answer is - (a) isobutene.

Explanation:

A 1° or primary hydrogen atom is one that is bonded to a 1° carbon atom; a 2° hydrogen atom is one that is connected to a 2° carbon atom; In isobutene only among all the all option having only primary hydrogen atoms. rest have secondary or teritary hydrogen atoms in them

C1∘H3≡CH: (only 1∘ hydrogen atoms)

4 0
2 years ago
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