The percent of SO₂ in H₂SO₄ : 65.3%
<h3>Further explanation
</h3>
Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements
%Mass A in AxBy =
For SO₂ in H₂SO₄ :
MW SO₂ = 32 + 2.16=64 g/mol
MW H₂SO₄ =2.1+32+4.16=98 g/mol
The percent of SO₂ :
Answer:
I'm sorry, but the person who answered this needs to do some research. The answer is C, no atoms are destroyed in the process.
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<span><span>
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Answer:
146.6 g
Explanation:
First we<u> calculate how many KNO₃ moles are there in 7.25 L of a 0.200 M solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.200 M * 7.25 L = 1.45 moles
Then we<u> convert 1.45 moles of KNO₃ into grams</u>, using its <em>molar mass</em>:
- 1.45 mol * 101.103 g/mol = 146.6 g
The answer should be c I believe
