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kumpel [21]
3 years ago
15

What is the frequency of a monochromatic light used in a diffraction experiment that has a wavelength of 6.38 ✕ 10e-07 m?

Physics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

f=4.70\times 10^{14}\ Hz

Explanation:

Given that,

The wavelength of light, \lambda=6.38\times 10^{-7}\ m

We need to find the frequency of the light. We know that,

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.38\times 10^{-7}}\\\\f=4.70\times 10^{14}\ Hz

So, the required frequency of light is equal to 4.70\times 10^{14}\ Hz.

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A solenoid with 435 turns has a length of 7.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find the solenoid's inductance a
OLga [1]

Answer:

Solenoid's inductance is 1.11 × 10^-8H

The average emf around the solenoid is 1.3 × 10^-5V

Explanation: Please see the attachments below

4 0
3 years ago
The x-component of vector R is Rx = −28.2 units and its y-component is Ry = 19.6 units. What are its magnitude and direction? Gi
ikadub [295]

Answer:

Explanation:

Rx = -28.2 units

Ry = 19.6 units

magnitude of R = √  [( - 28.2 )² + ( 19.6 ) ]

= √ ( 795.24 + 384.16 )

= 34.34 units

If θ  be the angle measured counterclockwise from the +x-direction

Tanθ = 19.6 / - 28.2 = -0.695

θ = 180 - 34.8

= 145.2° .

7 0
3 years ago
An apprentice bricklayer stabs 30cm long blocks on top of each other in such a way that 5cm of each block hangs over the lower b
NikAS [45]

Answer:

Explanation:The work done is twice as great for block B because it is moved twice the ... Equal forces are used to move blocks A and B across the floor. ... Does the normal force of the floor pushing upward on the block do any work? ... Suppose that the mass is halfway between one of the extreme points of its motion and the center point.

7 0
3 years ago
The magnitude of the velocity vector of the car is ∣∣v→∣∣ = 78 ft/s. If the vector v→ forms an angle θ = 0.09 rad with the horiz
kotegsom [21]

Answer:

\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

Explanation:

The x- and y- components of the velocity vector can be written as following:

\vec{v}_x = ||\vec{v}||\cos(\theta)\^i

\vec{v}_y = ||\vec{v}||\sin(\theta)\^j

Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

\vec{v} = 78\cos(0.09)\^i + 78\sin(0.09)\^j\\\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

3 0
3 years ago
81. A 560-g squirrel with a surface area of 930cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a
Irina18 [472]

Answer:

Explanation:

Given

mass of squirrel m=560 gm

Surface area of squirrel A=930 cm^2

and the area which face A_f=\frac{A}{2}=465 cm^2

height of tree h=5 m

Coefficient of drag C=1

drag Force F_d=\frac{1}{2}C\cdot \rho \cdot A\cdot v^2

Terminal velocity is given

F_d=mg

\frac{1}{2}C\cdot \rho \cdot A\cdot v^2=mg

v=\sqrt{\frac{2\times m\times g}{\rho \times C\times A_f}}

v=\sqrt{\frac{2\times 0.560\times 9.8}{1.2\times 1\times 465\times 10^{-4}}}

v=13.9 m/s

(b)Mass of person m=56 kg

v^2-u^2=2gh

u=0

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 5}

v=9.89 m/s

7 0
3 years ago
Read 2 more answers
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