True or false Induction works due to the movement of protons

The following three questions refer to a situation in which a driver is in a car that crashes into a solid wall. The car comes t

Andreas93 [3]

Answer:

1) p₀ = 45000 N / s , p₀ '= 1800 , b) I = -45000 N s , I = 1800 Ns

Explanation:

Impulse equals the change in momentum

I = Δp

1) the initial moment of the car

p₀ = M v

p₀ = 1500 30

p₀ = 45000 N / s

the change at the moment is

Δp = 45000

because the end the car is stopped

moment of the person

P₀ ’= m v

p₀ '= 60 30

p₀ '= 1800

D₀ '= 1800

2) of the momentum change impulse ratio

car

I = Δp

I = -45000 N s

person

I = Δpo '

I = 1800 Ns

3) the object that give the momentum to stop the wall motoring

The person is stopped by the impulse given by the car

a) This area is the one that absorbs most of the vehicle impulse

be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease

c) The air bag helps reduction in the speed of the person relatively quickly.

6 0

4 years ago

I REALLY NEED HELP

ikadub [295]

The first law of thermodynamics states the conservation of energy and heat where the total energy in an isolated system may be transformed into another, but never created or destroyed. If 286 J of energy was released to the room, then also 286 J of energy was also removed from food in that refrigerator assuming it is an isolated system. :)

Read more on Brainly - brainly.com/sf/question/3844753
I tried to help

3 0

3 years ago

A 160.-kilogram space vehicle is traveling along a straight line at a constant speed of 800. Meters per second. The magnitude of

natulia [17]

Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

4 0

3 years ago

Read 2 more answers

Discuss whether any work is being done by each of the following agents and, if so, whether the work is positive or negative: (a)

Aleks04 [339]

Answer:

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

Explanation:

Work is defined by the expression

W = F. r

bold letters indicate vectors, we can write this expression as a module

W= F r cos θ

where is at the angle between force and displacement.

Let's apply this expression to the different cases

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

7 0

4 years ago

Riders in an amusement park ride shaped like a Viking ship hung from a large pivot are rotated back and forth like a rigid pendu

erica [24]

Answer:

a) v = 16.57 m / s, b) a = 19.6 m / s², d) N = 1.76 10³ N, N / W = 3

Explanation:

This exercise looks interesting, but I think you have some problem with the writing, the questions seem a bit disconnected from the initial text.

Let's answer the questions.

a) For this part we can use energy considerations.

Starting point. The upper part of the trajectory indicates that the arm is horizontally

Em₀ = U = m g h

in this case h = r

Final point. For lower of the trajectory

Em_f = K = ½ m v²

as they indicate that there is no friction

Em₀ = em_f

mgh = ½ m v²

v = $\sqrt{2gh}$

let's calculate

v = $\sqrt{2 \ 9.8 \ 14.0}$

v = 16.57 m / s

b) the centripetal acceleration has the formula

a = v² / r

a = 16.57² / 14.0

a = 19.6 m / s²

c) see attached where the diagram is

where N is the normal and w the weight

d) let's use Newton's second law

N-W = m a

N - mg = m ar

N = m (g + a)

let's calculate

N = 60.0 (9.8 + 19.6)

N = 1.76 10³ N

the relationship with weight is

N / W = 1.76 10³/( 60 9.8)

N / W = 3

normal is three times greater than body weight

e) the answer is reasonable since by Newton's first law the body must continue in a straight line, therefore to change its trajectory a force must be applied to deflect it

6 0

3 years ago