For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as
K=4.08.3N/m
<h3>What is the spring constant?</h3>
Question Parameter(s):
a 25 kg car battery
The springs are pulled out by 0.06 meters
Generally, the equation for the Force is mathematically given as
F=mg
Therefore
F=(25*9.8)
(25*9.8)=K(0.06)
K=4.08.3N/m
In conclusion, the spring constant
K=4.08.3N/m
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Answer:
ΔV= -5.833×10⁻³
Negative sign indicates that volume decreases
Explanation:
Given data
System heat gains Q=3220 J
Pressure P=1.32×10⁵Pa
Internal energy increases ΔU=3990 J
To find
Change in volume ΔV
Solution
First we need to find the work done
So
W=Q-ΔU
W=3220J-3990J
W= -770J
Now for the change in volume at constant pressure
ΔV=(W/P)
ΔV= -5.833×10⁻³
Negative sign indicates that volume decreases
Question:
A high ____will have a short wavelength
Answer:
That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths
Explanation:
Hope it help
H = height of the pole = ?
BC = ED = height of the transit = 4 ft
CD = BE = distance moved away from the base of the pole = 140 ft
Consider the ΔABE
tan44 = AE/BE
tan44 = h/140
h = 140 tan44
h = 135.2 ft
H = height of pole = AE + ED = h + ED = 135.2 + 4
H = 139.2 ft